Dr. Anita Goel – Studying DNA Using Physics
Anita Goel, MD, PhD, is another example of a polymath who is able to combine seemingly disparate disciplines to understand natural phenomena – physics and genetics. Named one of the world’s 35 most promising researchers under the age of 35 by MIT’s Technology Review Magazine, Dr. Goel of Harvard University is studying how DNA polymerase replicates DNA.
“There’s this sense of wonder, with a lot of nature around you,” Goel said. “We understand so much about atoms and molecules, but do we really understand the basic physics of life?”
Dr. Goel likens DNA polymerase to a nanoscale motor that converts chemical energy into mechanical energy as it moves along a strand of DNA. In addition to studying DNA replication, she is developing new methods for detecting viruses and bacteria with potential use in counter-terrorism. This work is performed with her company, Nanobiosym.
Harvard University Gazette, December 8, 2005
Counter terrorism sounds real good, but let’s be more pragmatic and start developing cures for known diseases such as HIV and cancer. That would be something really useful.
NAME: BAIDYANATH DASH
STUDENT, FINAL SEMESTER,
B.E(MEDICAL-ELECTRONICS);
DAYANANDA SAGAR COLLEGE OF ENGINEERING,BANGALORE-560078,INDIA
THESIS WORK
We know,
from HEISENBERG’S UNCERTAINTY PRINCIPLE,
delta E* dalta t=h/2pi;
=6.023*10^-23/2pi;
Also, we know, 6 fragments of dna make’ LIFE’.
2pi is measure of one cycle or circle.
According to Bose-Einstein,
‘
life or soul’ is made of cooper-pairs.
Here, we take 1 Helical turn as one cycle or
circle. As cooper pairs are RESONATING,they are
not perfect circles,but helical.They exhibit
electromagnetic properties.
Also,23/6.023=3.5, which is distance between 2
base pairs.Here 23 is negative power of the equation.
Hence life can be made of 6 circles,or 3 cooper
pairs(6 DNA TURNS),2pi foir 1 circle,or 1 helical
turn.As, structure is helical,’ sign’(greater or
equal to) is used in Heisenberg’s equation.
The waveform configuration of cooper-pair shows
superimposition of 2 waves coming from opposite
directions, as in DNA where 2 strands are in 5-3′
AND 3′-5′.
Thanking You,
Yours sincerely,
BAIDYANATH DASH
ADRESS:
BAIDYANATH DASH,
C/O: VINAYAKA ENTERPRISE,# 104,71ST CROSS,K.S.LAYOUT,BANGALORE,560078,INDIA,E-MAIL: bn_dash2002@yahoo.co.in/baidyanath22@gmail.com
ADRESS:
BAIDYANATH DASH
C/O VINAYAKA ENTERPRISES,
#104.K.S.LAYOUT,71ST CROSS,
BANGALORE-560078,INDIA
E MAIL: bn_dash2002@yahoo.co.in/
baidyanath22@gmail.com.
PROOF OF THESIS : ‘RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) UNIVERSE IS MADE OF
a)SPACE(3 DIMENSIONAL)
b)TIME(1 DIM.)
c)MATTER(PARTICLE AND WAVE NATURE).
THEREFORE, 3+1+2=6 .
2) TOTAL NO. OF STARS(APPROX.)IN THE UNIVERSE =10^23.
3) COMBINATION OF 6(COMPONENTS)10^23(1 UNIVERSE).
4) PLANK’S CONSTANT=6.023*10^-23.
5) E*T= deltaE.deltaT*double integral(-infinite to zero, zero to infinite)(deltaE . deltaT)dE.Dt =1 .
6) LET SOURCE BE 1(ONE INDIVIDUAL)>= 6.023*10^-23*10^23
2PI
>= 6.023*10^-23*10^23
2PI
>= 1
7)CASES: 1)SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
2)THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
8)THEREFORE, UNIT OF LIFE IS MADE OF 3 COOPER PAIRS.
– BAIDYANATH DASH
B.E(MEDICAL ELECTRONICS)
THESIS WORK
We know,
from HEISENBERG’S UNCERTAINTY PRINCIPLE,
delta E* dalta t=h/2pi;
=6.023*10^-23/2pi;
Also, we know, 6 fragments of dna make’ LIFE’.
2pi is measure of one cycle or circle.
According to Bose-Einstein,
‘
life or soul’ is made of cooper-pairs.
Here, we take 1 Helical turn as one cycle or
circle. As cooper pairs are RESONATING,they are
not perfect circles,but helical.They exhibit
electromagnetic properties.
Also,23/6.023=3.5, which is distance between 2
base pairs.Here 23 is negative power of the equation.
Hence life can be made of 6 circles,or 3 cooper
pairs(6 DNA TURNS),2pi for 1 circle,or 1 helical
turn.As, structure is helical,’ sign’(greater or
equal to) is used in Heisenberg’s equation.
The waveform configuration of cooper-pair shows
superimposition of 2 waves coming from opposite
directions, as in DNA where 2 strands are in 5-3′
AND 3′-5′.
PROOF OF THESIS : ‘RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) UNIVERSE IS MADE OF
a)SPACE(3 DIMENSIONAL)
b)TIME(1 DIM.)
c)MATTER(PARTICLE AND WAVE NATURE).
THEREFORE, 3+1+2=6 .
2) TOTAL NO. OF STARS(APPROX.)IN THE UNIVERSE =10^23.
3) COMBINATION OF 6(COMPONENTS)10^23(1 UNIVERSE).
4) PLANK’S CONSTANT=6.023*10^-23.
5) E*T= deltaE.deltaT*double integral(-infinite to zero, zero to infinite)(deltaE . deltaT)dE.Dt =1 .
6) LET SOURCE BE 1(ONE INDIVIDUAL)>= 6.023*10^-23*10^23
2PI
>= 6.023*10^-23*10^23
2PI
>= 1
7)CASES: 1)SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
2)THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
8)THEREFORE, UNIT OF LIFE IS MADE OF 3 COOPER PAIRS.
- BAIDYANATH DASH
B.E(MEDICAL ELECTRONICS),
BANGALORE, (INDIA).
Dear Madam,
I have some more thoughts and explanations on same topic.I will post them to you.I hope, you will help me in have your own opinion . I want this paper be sent to the respective scientific community concerned.In this regard I want to thank you a lot in keeping the same with your blog. Thank you very much ,madam.
Madam, the thesis I had sent is correct ,I hope. Can you further give some opinions. I will send my some more work on it shortly.I am trying TO send it to some scientific community. Please help.
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population , there are 3 X and 1 Y chromosome(3: 1 ratio) in gene pool.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3) We know, 1 cooper pair is overlapped by 10^6 cooper pairs.
4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on
oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Means, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —-> 4 He
(1) 0 2
2) 4 He Reverse—-> 4 1 H + 2 0 e
2 (hypothetical) 1(-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —-> 4 He
(1) 0 2
2) 4 He Reverse—-> 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
Relation between Heisenberg’s uncertainty principle and DNd – double helix:
1) From, HEISENBERG’S UNCERTAINTY PRINCIPLE,
delta E* delta t =h/2pi joules.second;
=6.023*10^-23 joules.second;
2pi
=6.023*10^-20*10^-3 joules.second;
2pi
=6.023*10^-20 joules.millisecond;
2pi
2) Also, we know, 6 fragments of DNA make’ LIFE’.
3) 2pi is measure of one cycle or circle.
4) According to Bose-Einstein,
‘Life or Soul’ is made of cooper-pairs.
5) Here, we take 1 Helical turn as one cycle or circle(2pi). As
cooper pairs are RESONATING, they are not perfect circles,but
helical.They exhibit electromagnetic properties.
6) Also,23/6.023=3.5, which is distance between 2 base pairs. Here
23 is negative power of the equation.
7) Hence, life can be made of 6 circles, or 3 cooper pairs (6 DNA
TURNS) ,2pi for 1 circle,or 1 helical turn.As, structure is helical,’
sign’(greater or equal to) is used in Heisenberg’s equation.
2 waves coming from opposite directions, as in DNA where 2 strands
are in 5′-3′ and 3′-5′ .
PROOF OF THESIS : “RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) UNIVERSE IS MADE OF
a)SPACE(3 DIMENSIONAL)
b)TIME(1 DIM.)
c)MATTER(PARTICLE AND WAVE NATURE).
THEREFORE, 3+1+2=6 .
2) TOTAL NO. OF STARS(APPROX.)IN THE UNIVERSE =10^23.
3) COMBINATION OF 6(COMPONENTS)10^23(1 UNIVERSE).
4) PLANK’S CONSTANT=6.023*10^-23.
5) E*T= deltaE.deltaT*double integral(-infinite to zero, zero to
6) infinite)(deltaE . deltaT)dE.dT =1 .
7) LET SOURCE BE 1(ONE INDIVIDUAL)>= 6.023*10^-23*10^23
2PI
>= 6.023*10^-23*10^23
2PI
>= 1
7)CASES:
1)SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
2)THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
8)THEREFORE, UNIT OF LIFE IS MADE OF 3 COOPER PAIRS.
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population, there are 3 X and 1 Y chromosome(3:1 ratio) in gene pool.
In Y chromosome ‘something’ is present. It is neutron(=proton and electron). Rest, X chromosomes are similar, which we can take them as electron.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3) We know, 1 cooper pair is overlapped by 10^6 cooper pairs. 4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Now, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
BAIDYANATH DASH
B.E(MEDICAL ELECTRONICS)
I AM NOW THINKING HOW THIS BETA PARTICLE ACTS THE PURPOSE OF ELECTRONS.
We get,mass of beta particles to mass of electron is 10^6.
Hence,2*10^6 electrons corrosponds to a two(2) beta particle.The spiritual velocity of the beta particle (9.40314375*10^9 m/s may be that of “thought”.
1)2 beta-particles with velocity 9.4*10^9 m/s must have same energy that of 2 electrons with velocity 3*10^8 m/s.
2) Therefore,
E(beta)=mass of beta-particles *square of (velocity of beta-particles)
=2*(1.6*10^-24)*square of(9.4*10^9)
1837
=1.539*10^-7 Joules.
E(electron)=2*9.1*10^-31*square of(3*10^8)
=1.5*10-7 Joules.
3)Hence, 2 beta-particles with velocity 9.4*10^9 m/s serves the purpose of of 2 electrons with velocity 3*10^8 m/s.
ERROR RECRTIFICATION:
E(electron) or energy of electron=2*9.1*10^-31*(10^6)*squre of(3*10^8)
=1.5*10^7 joules
ERROR RECRTIFICATION:
E(electron) or energy of electron=2*9.1*10^-31*(10^6)*squre of(3*10^8)
=1.5*10^-7 joules
Hence,2*10^6 electrons (with velocity 3*10^8 m/s)means 10^6 cooper pairs has same energy that of 2 beta-particle with velocity of 9.4*10^9 m/s.
Thus, this confirms that 3 cooper pairs are basis for life.
BAIDYANATH DASH says:
April 25, 2009 at 7:07 am
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —-> 4 He
(1) 0 2
2) 4 He Reverse—-> 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
Reply
BAIDYANATH DASH says:
April 25, 2009 at 7:09 am
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
Reply
BAIDYANATH DASH says:
April 25, 2009 at 7:27 am
Relation between Heisenberg’s uncertainty principle and DNd – double helix:
1) From, HEISENBERG’S UNCERTAINTY PRINCIPLE,
delta E* delta t =h/2pi joules.second;
=6.023*10^-23 joules.second;
2pi
=6.023*10^-20*10^-3 joules.second;
2pi
=6.023*10^-20 joules.millisecond;
2pi
2) Also, we know, 6 fragments of DNA make’ LIFE’.
3) 2pi is measure of one cycle or circle.
4) According to Bose-Einstein,
‘Life or Soul’ is made of cooper-pairs.
5) Here, we take 1 Helical turn as one cycle or circle(2pi). As
cooper pairs are RESONATING, they are not perfect circles,but
helical.They exhibit electromagnetic properties.
6) Also,23/6.023=3.5, which is distance between 2 base pairs. Here
23 is negative power of the equation.
7) Hence, life can be made of 6 circles, or 3 cooper pairs (6 DNA
TURNS) ,2pi for 1 circle,or 1 helical turn.As, structure is helical,’
sign’(greater or equal to) is used in Heisenberg’s equation.
The waveform configuration of cooper-pair shows superimposition of
2 waves coming from opposite directions, as in DNA where 2 strands
are in 5′-3′ and 3′-5′ .
PROOF OF THESIS : “RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) UNIVERSE IS MADE OF
a)SPACE(3 DIMENSIONAL)
b)TIME(1 DIM.)
c)MATTER(PARTICLE AND WAVE NATURE).
THEREFORE, 3+1+2=6 .
2) TOTAL NO. OF STARS(APPROX.)IN THE UNIVERSE =10^23.
3) COMBINATION OF 6(COMPONENTS)10^23(1 UNIVERSE).
4) PLANK’S CONSTANT=6.023*10^-23.
5) E*T= deltaE.deltaT*double integral(-infinite to zero, zero to
6) infinite)(deltaE . deltaT)dE.dT =1 .
7) LET SOURCE BE 1(ONE INDIVIDUAL)>= 6.023*10^-23*10^23
2PI
>= 6.023*10^-23*10^23
2PI
>= 1
7)CASES:
1)SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
2)THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
8)THEREFORE, UNIT OF LIFE IS MADE OF 3 COOPER PAIRS.
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population, there are 3 X and 1 Y chromosome(3:1 ratio) in gene pool.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3) We know, 1 cooper pair is overlapped by 10^6 cooper pairs. 4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Now, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
In Y chromosome ‘something’ is present. It is neutron(=proton and electron). Rest, X chromosomes are similar, which we can take them as electron.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material.
MRI magnets are made of He.
We get,mass of beta particles to mass of electron is 10^6.
Hence,2*10^6 electrons corrosponds to a two(2) beta particle.The spiritual velocity of the beta particle (9.40314375*10^9 m/s may be that of “thought”.
)2 beta-particles with velocity 9.4*10^9 m/s must have same energy that of 2 electrons with velocity 3*10^8 m/s.
2) Therefore,
E(beta)=mass of beta-particles *square of (velocity of beta-particles)
=2*(1.6*10^-24)*square of(9.4*10^9)/1837
=1.539*10^-7 Joules.
Hence,2*10^6 electrons (with velocity 3*10^8 m/s)means 10^6 cooper pairs has same energy that of 2 beta-particle with velocity of 9.4*10^9 m/s.
Thus, this confirms that 3 cooper pairs are basis for life.
E(electron)=2*9.1*10^-31*square of(3*10^8)
=1.5*10-7 Joules.
3)Hence, 2 beta-particles with velocity 9.4*10^9 m/s serves the purpose of of 2 electrons with velocity 3*10^8 m/s.
ERROR RECRTIFICATION:
E(electron) or energy of electron=2*9.1*10^-31*(10^6)*squre of(3*10^8)
=1.5*10^-7 joules
Relation between Heisenberg’s uncertainty principle and DNA – double helix:
1) From, HEISENBERG’S UNCERTAINTY PRINCIPLE,
delta E* delta t =h/2pi joules.second;
=6.023*10^-23 joules.second;
2pi
=6.023*10^-20*10^-3 joules.second;
2pi
=6.023*10^-20 joules.millisecond;
2pi
2) Also, we know, 6 fragments of DNA make’ LIFE’.
3) 2pi is measure of one cycle or circle.
4) According to Bose-Einstein,
‘Life or Soul’ is made of cooper-pairs.
5) Here, we take 1 Helical turn as one cycle or circle(2pi). As
cooper pairs are RESONATING, they are not perfect circles,but
helical.They exhibit electromagnetic properties.
6) Also,23/6.023=3.5, which is distance between 2 base pairs. Here
23 is negative power of the equation.
7) Hence, life can be made of 6 circles, or 3 cooper pairs (6 DNA
TURNS) ,2pi for 1 circle,or 1 helical turn.As, structure is helical,’
sign’(greater or equal to) is used in Heisenberg’s equation.
The waveform configuration of cooper-pair shows superimposition of
2 waves coming from opposite directions, as in DNA where 2 strands
are in 5′-3′ and 3′-5′ .
PROOF OF THESIS : “RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) UNIVERSE IS MADE OF
a)SPACE(3 DIMENSIONAL)
b)TIME(1 DIM.)
c)MATTER(PARTICLE AND WAVE NATURE).
THEREFORE, 3+1+2=6 .
2) TOTAL NO. OF STARS(APPROX.)IN THE UNIVERSE =10^23.
3) COMBINATION OF 6(COMPONENTS)10^23(1 UNIVERSE).
4) PLANK’S CONSTANT=6.023*10^-23.
5) E*T= deltaE.deltaT*double integral(-infinite to zero, zero to
6) infinite)(deltaE . deltaT)dE.dT =1 .
7) LET SOURCE BE 1(ONE INDIVIDUAL)>= 6.023*10^-23*10^23
2PI
>= 6.023*10^-23*10^23
2PI
>= 1
7)CASES:
1)SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
2)THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
8)THEREFORE, UNIT OF LIFE IS MADE OF 3 COOPER PAIRS.
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population, there are 3 X and 1 Y chromosome(3:1 ratio) in gene pool.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3) We know, 1 cooper pair is overlapped by 10^6 cooper pairs. 4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Now, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
In Y chromosome ‘something’ is present. It is neutron(=proton and electron). Rest, X chromosomes are similar, which we can take them as electron.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material.
MRI magnets are made of He.
We get,mass of beta particles to mass of electron is 10^6.
Hence,2*10^6 electrons corrosponds to a two(2) beta particle.The spiritual velocity of the beta particle (9.40314375*10^9 m/s may be that of “thought”.
)2 beta-particles with velocity 9.4*10^9 m/s must have same energy that of 2 electrons with velocity 3*10^8 m/s.
2) Therefore,
E(beta)=mass of beta-particles *square of (velocity of beta-particles)
=2*(1.6*10^-24)*square of(9.4*10^9)/1837
=1.539*10^-7 Joules.
Hence,2*10^6 electrons (with velocity 3*10^8 m/s)means 10^6 cooper pairs has same energy that of 2 beta-particle with velocity of 9.4*10^9 m/s.
Thus, this confirms that 3 cooper pairs are basis for life.
E(electron)=2*9.1*10^-31*square of(3*10^8)
=1.5*10-7 Joules.
3)Hence, 2 beta-particles with velocity 9.4*10^9 m/s serves the purpose of of 2 electrons with velocity 3*10^8 m/s.
ERROR RECRTIFICATION:
E(electron) or energy of electron=2*9.1*10^-31*(10^6)*squre of(3*10^8)
=1.5*10^-7 joules
THANK YOU….
………*******………
1)E=M*C^2
=M*C*C
=(2 dim.)+(2dim.)+(2dim.)
=10^2*10^2*10^2
=10^6.
2) Velocity of light=3*10^8 m/s.
=(3 dim.)*10^2*10^2*10^2
3) We note here that, for calculating universal bodies, we use power of 10 and multiplication.
4)For 3 dimensions, 3 is multiplied. Also, 10^2 is multiplied 3 times; each for 1 dimension.
5) Similarly,
By power shifting and rewriting equation we have ,
(3)2*10^3*10^3*10^3 ; (Not 3^2*10^2*10^2*10^2)
=9*10^9.
This is a new velocity which is more than velocity of light(i.e 9*10^9 m/s).
6)NUMERICALS:
We notice that if we add the digits in all powers of 6 , it is divisible by 9 (except 6^1).eg. 6^3=216; (2+1+6=9 which is divisible by 9).
7)We find, 10^6 times energy of electron equals energy of beta-particle.
10^6 * Energy = Energy
(electron) (beta-particle)
8)Hence, 1) Energy(beta) has beta-particles with velocity 9*10^9 m/s
2) It is 10^6 times that of Energy(electrons).
*******************
Relation between Heisenberg’s uncertainty principle and DNA – double helix:
1) From, HEISENBERG’S UNCERTAINTY PRINCIPLE,
delta E* delta t =h/2pi joules.second;
=6.023*10^-23 joules.second;
2pi
=6.023*10^-20*10^-3 joules.second;
2pi
=6.023*10^-20 joules.millisecond;
2pi
2) Also, we know, 6 fragments of DNA make’ LIFE’.
3) 2pi is measure of one cycle or circle.
4) According to Bose-Einstein,
‘Life or Soul’ is made of cooper-pairs.
5) Here, we take 1 Helical turn as one cycle or circle(2pi). As
cooper pairs are RESONATING, they are not perfect circles,but
helical.They exhibit electromagnetic properties.
6) Also,23/6.023=3.5, which is distance between 2 base pairs. Here
23 is negative power of the equation.
7) Hence, life can be made of 6 circles, or 3 cooper pairs (6 DNA
TURNS) ,2pi for 1 circle,or 1 helical turn.As, structure is helical,’
sign’(greater or equal to) is used in Heisenberg’s equation.
The waveform configuration of cooper-pair shows superimposition of
2 waves coming from opposite directions, as in DNA where 2 strands
are in 5′-3′ and 3′-5′ .
PROOF OF THESIS : “RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) UNIVERSE IS MADE OF
a)SPACE(3 DIMENSIONAL)
b)TIME(1 DIM.)
c)MATTER(PARTICLE AND WAVE NATURE).
THEREFORE, 3+1+2=6 .
2) TOTAL NO. OF STARS(APPROX.)IN THE UNIVERSE =10^23.
3) COMBINATION OF 6(COMPONENTS)10^23(1 UNIVERSE).
4) PLANK’S CONSTANT=6.023*10^-23.
5) E*T= deltaE.deltaT*double integral(-infinite to zero, zero to
6) infinite)(deltaE . deltaT)dE.dT =1 .
7) LET SOURCE BE 1(ONE INDIVIDUAL)>= 6.023*10^-23*10^23
2PI
>= 6.023*10^-23*10^23
2PI
>= 1
7)CASES:
1)SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
2)THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
8)THEREFORE, UNIT OF LIFE IS MADE OF 3 COOPER PAIRS.
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population, there are 3 X and 1 Y chromosome(3:1 ratio) in gene pool.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3) We know, 1 cooper pair is overlapped by 10^6 cooper pairs. 4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Now, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
In Y chromosome ‘something’ is present. It is neutron(=proton and electron). Rest, X chromosomes are similar, which we can take them as electron.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
(1) 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 1 proton in Hydrogen gives 2 electrons in the Reverse nuclear reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material.
MRI magnets are made of He.
We get,mass of beta particles to mass of electron is 10^6.
Hence,2*10^6 electrons corrosponds to a two(2) beta particle.The spiritual velocity of the beta particle (9.40314375*10^9 m/s may be that of “thought”.
)2 beta-particles with velocity 9.4*10^9 m/s must have same energy that of 2 electrons with velocity 3*10^8 m/s.
2) Therefore,
E(beta)=mass of beta-particles *square of (velocity of beta-particles)
=2*(1.6*10^-24)*square of(9.4*10^9)/1837
=1.539*10^-7 Joules.
Hence,2*10^6 electrons (with velocity 3*10^8 m/s)means 10^6 cooper pairs has same energy that of 2 beta-particle with velocity of 9.4*10^9 m/s.
Thus, this confirms that 3 cooper pairs are basis for life.
E(electron)=2*9.1*10^-31*square of(3*10^8)
=1.5*10-7 Joules.
3)Hence, 2 beta-particles with velocity 9.4*10^9 m/s serves the purpose of of 2 electrons with velocity 3*10^8 m/s.
ERROR RECRTIFICATION:
E(electron) or energy of electron=2*9.1*10^-31*(10^6)*squre of(3*10^8)
=1.5*10^-7 joules
1)E=M*C^2
=M*C*C
=(2 dim.)+(2dim.)+(2dim.)
=10^2*10^2*10^2
=10^6.
2) Velocity of light=3*10^8 m/s.
=(3 dim.)*10^2*10^2*10^2
3) We note here that, for calculating universal bodies, we use power of 10 and multiplication.
4)For 3 dimensions, 3 is multiplied. Also, 10^2 is multiplied 3 times; each for 1 dimension.
5) Similarly,
By power shifting and rewriting equation we have ,
(3)2*10^3*10^3*10^3 ; (Not 3^2*10^2*10^2*10^2)
=9*10^9.
This is a new velocity which is more than velocity of light(i.e 9*10^9 m/s).
6)NUMERICALS:
We notice that if we add the digits in all powers of 6 , it is divisible by 9 (except 6^1).eg. 6^3=216; (2+1+6=9 which is divisible by 9).
7)We find, 10^6 times energy of electron equals energy of beta-particle.
10^6 * Energy = Energy
(electron) (beta-particle)
8)Hence, 1) Energy(beta) has beta-particles with velocity 9*10^9 m/s
2) It is 10^6 times that of Energy(electrons).
ERROR RECTIFICATION:
1) mass of beta-particle / mass of electron=9.5 * 10^3.
Hence,2*10^6 electrons corrosponds to a two(2) beta particle.The spiritual velocity of the beta particle (9.40314375*10^9 m/s may be that of “thought”.
*******************
BAIDYANATH DASH
B.E(MEDICAL ELECTRONICS)
ERROR RECTIFICATION:
In nuclear reaction,
4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 (-1)
we see that, mass of is negligible on “e”,; so it wii be either electron or beta, but as mass of electron is less, it suits here, Again, from energy equivalence we find it is betparticles. Mass here is compensated by heat energy.
NOTE:
1) 25% OF 17(APART FROM WATER) = 4.25%(1 pair corresponds to 4.25- 4.5% ) WHICH CONSISTS OF FAT, PROTEIN, VITAMINS, MINERALS,ETC.
2) Velocity of light= 3*10^8 m/s.
= (3*1 dim.)*10^2*10^2*10^2*10^2 m/s.
We get here that, there are 3 dimensions and also a dimension which “touches” all three. May be that is 4th dim. This shows,10^2 corrosponds to 4th dimension .Hence, 4 times multiplication of 10^2 is done. Interestingly, by mathematics, 3*1=3 .
Relation between Heisenberg’s uncertainty principle
and DNA double- helix:
1) From, Heisenberg’s Uncertainty Principle,
delta E* delta t =h/2pi j.s
=6.6*10^-34/2pi j.s;
=6.6*10^-32*10^-2/2pi j.s .
= 1.05*10^-34 j.s.
We know, 6 DNA fragments make life.6.6(not 7 complete). Hence 6 DNA fragments.
32Angstrom and 24Angstrom are length and breadth of DNA strand respectively.
Difference(32 -24 )Angstrom=8 Angstrom.Due to this difference, DNA strand is helical in shape.
For smaller particles(like DNA and unlike heavenly bodies),8 Angstrom=(10-2)Angstrom=>10^-2.
2pi corresponds to 1 cycle(of DNA strand).
Hence, life can be made of 6 circles, or 3 cooper pairs (6 DNA
turns) ,2pi for 1 circle,or 1 helical turn.As, structure is helical,’
sign’(greater or equal to) is used in Heisenberg’s equation.
The waveform configuration of cooper-pair shows superimposition of
2 waves coming from opposite directions, as in DNA where 2 strands
are in 5′-3′ and 3′-5′ .
PROOF OF THESIS : “RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) Universe is composed of 3 components:
a)Space(3 dim.)
b)Time(1 dim.)
c)Matter(2 dim.)
Therefore, 3+1+2=6 (also, 3*2*1=6)
2) Total number of stars=10^22.
3) Combinaton of 6(components)=10^6.
4) Planck’s constant =6.6*10^-34 JS.
5)For heavenly bodies, for calculating universal bodies, we use power of 10
and multiplication.
6)We can correspond a DNA strand to shape of Universe.32 Angstrom becomes 10^34 and 24 Angstrom becomes 10^24.
7)Now let,
(deltaE*deltaT)*((double integral)(deltaE*deltaT dE.dT)) =1
Therefore,
(6.6*10^-34/2pi)*(10^32*10^24/10^22)>=1
This shows that our assumption is correct.Hence, life may be made of 3 cooper pairs. As a small piece of magnet is also a magnet, likewise, the whole composition is built by 3 cooper pairs.
*>SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
*>THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population, there are 3 X and 1 Y chromosome(3:1 ratio) in gene pool.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3)We know, 1 cooper pair is overlapped by 10^6 cooper pairs.
4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Now, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
9) In Y chromosome ‘something’ is present. It is neutron(=proton and electron). Rest, X chromosomes are similar, which we can take them as electron.
10)Therefore, there are 1 electron-electron pair and 1 electron-neutron pair.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
1 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 -1
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 2 neutrons give 2 electrons and 2 protons in the Reverse nuclear
reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
7)The above mentioned reverse reaction has 2 electrons on R.H.S. Mass mentioned is negligible. beta-particles(negatively charged particles which has mass 1/1837 than that of proton.
8)Energy remains same either for particle or wave nature.
9)Therefore, keeping energy same,
10)E=m*c^2
=9.1*10^-31*(9*10^16)
=8.19*10^-14 J.
*> NEW FINDING(By mistake!)
11)Now, 8.19*10^-14=mass of beta-particle*velocity(spiritual)
Therefore, velocity(spiritual)=1.89*10^-14/mass of beta-particle.
=(8.19*10^-14*1837*10-1)/(1.6*10^-24)
=9.40314375*10^9 m/s.
12)We know, beta-particles originates from brain(in EEG), through eyes.
Now, 2 beta-particles with velocity 9.7*10^9 m/s must have same energy that of 2 electrons with velocity 3*10^8 m/s.
13)Therefore,
E(beta)=mass of beta-particles *square of (velocity of beta-particles)
=(1.6*10^-24)*square of(9.7*10^9)
1837
=8.1*10^-8 Joules.
E(electron)=9.1*10^-31*square of(3*10^8)*10^6
=8.1*10^-8 Joules.
Hence, 2 beta-particles with velocity 9.7*10^9 m/s serves the purpose of 2 electrons with velocity 3*10^8 m/s.
*****
NUMERICALS:
1)E=M*C^2
=M*C*C
=(2 dim.)+(2dim.)+(2dim.)
=10^2*10^2*10^2
=10^6.
2) Velocity of light=3*10^8 m/s.
=(3*1 dim.)*10^2*10^2*10^2*10^2 m/s.
We get here that, there are 3 dimensions and also a dimension which “touches” all three. May be that is 4th dim. This shows,10^2 corrosponds to 4th dimension .Hence, 4 times multiplication of 10^2 is done. Interestingly, by mathematics, 3*1=3 .
3) Similarly,
By power shifting and rewriting equation we have ,
(3)^2*10^3*10^3*10^3 ; (Not
=9*10^9.
This is a new velocity which is more than velocity of light(i.e 9*10^9 m/s).
4)We find, 10^6 times energy of electron equals energy of beta-particle.
10^6 * Energy = Energy
(electron) (beta-particle)
5)Hence, 1) Energy(beta) has beta-particles with velocity 9*10^9 m/s
2) It is 10^6 times that of Energy(electrons).
*> We notice that if we add the digits in all powers of 6 , it is divisible by 9 (except 6^1).eg. 6^3=216; (2+1+6=9 which is divisible by 9).
— BAIDYANATH DASH
B.E(MEDICAL ELECTRONICS)
yes, 25% OF 17(apart from water)=4.25%(1 pair corresponds to 4.25- 4.5%).
Because,75% has carbohydrate, I suppose.
I am shameful that I took wrong value of Planck’s constant(h). Now, I came up with new thoughts and ideas, but methodology is same.I truly grateful for your support that you gave me a platform where I did my’NET PRACTICE’. Ha..ha. With lots of regards and love, I again thank you.
Respected madam, I have applied my paper to Nobel Committee.Your kind blessing is needed.
TO FIND DENSITY OF UNIVERSE BY DNA DOUBLE HELIX STRUCTURE :
E(proton)/E(electron)=1.44*10^-7/8.19*10^-14=1.7*10^6.
Let us take dimensions of DNA as 34 angstrom and 26 angstrom.
Therefore, Volume of DNA strand = (4/3)*PI*((17 angstrom)^3 –(4 angstrom)^3))
= 2.0301*10^-26 m^3.
We have,
1)1 cooper pair is overlapped by 10^6 cooper pairs.(so, 10^12 electron overlapping)
2) 1 nucleotide has 10^6 cooper pairs.
3) 1 DNA strand has 1 million(or 10^6) nucleotides.
Therefore,
(10^6*10^6*10^6*10^6)*E(beta)*E(proton)/E(electron) =density*( 2.0301*10^-26 )*C^2.
or, (8.19*10^-8) *(1.76*10^6) *10^24= density*( 2.0301*10^-26 )*C^2.
or, 8.19*1.76*10^24 = density*18*10^-10
Density = 8.0* 10^31. Kg/m^3.
We note that this density is “Before” Big -Bang .
After Big-Bang, when universe is formed, density decreases.
Therefore,
Density(universe)=1/(8*10^31)
=1.25*10^-29 g/cm^3 .
Relation between Heisenberg ’s uncertainty principle and DNA double- helix:
1) From, Heisenberg’s Uncertainty Principle
delta E* delta t =h/2pi j.s
=6.6*10^-32*10^-2/2pi j.s .
. =6.6*10^-34/2pi j.s;
= 1.05*10^-34 j.s
2) We know, 6 DNA fragments make life.6.6(not 7 complete). Hence 6 DNA fragments.
32Angstrom and 24Angstrom are length and breadth of DNA strand respectively.
3) Difference(32 -24 )Angstrom=8 Angstrom.Due to this difference, DNA strand is helical in shape.
For smaller particles(like DNA and unlike heavenly bodies),8 Angstrom=(10-2)Angstrom=>10^-2.
4) 2pi corresponds to 1 cycle(of DNA strand).
5) Hence, life can be made of 6 circles, or 3 cooper pairs (6 DNA
turns) ,2pi for 1 circle,or 1 helical turn.As, structure is helical,’
sign’(greater or equal to) is used in Heisenberg’s equation.
6) The waveform configuration of cooper-pair shows superimposition of
2 waves coming from opposite directions, as in DNA where 2 strands
are in 5′-3′ and 3′-5′ .
PROOF OF THESIS : “RELATIONSHIP BETWEEN HEISENBERG’S UNCERTAINTY PRINCIPLE AND DNA DOUBLE HELIX”.
1) Universe is composed of 3 components:
a)Space(3 dim.)
b)Time(1 dim.)
c)Matter(2 dim.)
Therefore, 3+1+2=6 (also, 3*2*1=6)
1) Total number of stars=10^22.
2) Combinaton of 6(components)=10^6.
3) Planck’s constant =6.6*10^-34 JS.
5)For heavenly bodies, for calculating universal bodies, we use power of 10
and multiplication.
6)We can correspond a DNA strand to shape of Universe.32 Angstrom becomes 10^34 and 24 Angstrom becomes 10^24.
7)Now let,
(deltaE*deltaT)*((double integral)(deltaE*deltaT dE.dT)) =1
Therefore,
(6.6*10^-34/2pi)*(10^32*10^24/10^22)>=1
This shows that our assumption is correct.Hence, life may be made of 3 cooper pairs. As a small piece of magnet is also a magnet, likewise, the whole composition is built by 3 cooper pairs.
>SUM OF ALL SMALL PARTICLES IS MORE THAN THE INTEGRAL.
>THE WHOLE IS GREATER THAN SUM OF ITS PARTS.
-(MAX WERTHEIMER).
FURTHER INSIGHTS:
1)From biological perspective, assuming 50% male and 50% female population, there are 3 X and 1 Y chromosome(3:1 ratio) in gene pool.
2)Assume, X corresponds to electrons and Y corresponds to neutron. So,we have one 2-electron pair(cooper pair) and an electron-neutron pair.
3)We know, 1 cooper pair is overlapped by 10^6 cooper pairs.
4)Also, millions(10^6)nucleotides overlap to form a DNA strand.
5)There is 1 to 1 relationship between an electron and a photon.
6)Human body consists of 83% water. Water has a lone-pair electron on oxygen .It may act as a cooper pair. Also, rest 75%(of 17%) is carbohydrate. Now, 75% of 17% equals 12.75%.So, it becomes 95.75%(approx. values). Rest 4.25%-5% are fat, protein, vitamins and minerals.
7) If (22+1) pair chromosomes corresponds to 100%, then, 22 pair is 95% of (22+1) pair chromosomes. And, 1 pair corresponds to 4.5% .
9) In Y chromosome ‘something’ is present. It is neutron(=proton and electron). Rest, X chromosomes are similar, which we can take them as electron.
10)Therefore, there are 1 electron-electron pair and 1 electron-neutron pair.
NUCLEAR REACTIONS:
1) 2 1 H + 2 1 n —- 4 He
1 0 2
2) 4 He Reverse—- 4 1 H + 2 0 e
2 (hypothetical) 1 -1
3) We know at surface of Sun, Hydrogen glows to form He(core).
4) 2 neutrons give 2 electrons and 2 protons in the Reverse nuclear
reaction.
5) In Y chromosome, 1 electron and 1 neutron(=electron and proton) is present. Now, we have total 6 electrons, ie. 3 cooper pairs.
6) Helium is a superconducting material. MRI magnets are made of He.
7)The above mentioned reverse reaction has 2 electrons on R.H.S. Mass mentioned is negligible. beta-particles(negatively charged particles which has mass 1/1837 than that of proton.
8)Energy remains same either for particle or wave nature.
-
9)Therefore, keeping energy same,
10)E=m*c^2
=9.1*10^-31*(9*10^16)
=8.19*10^-14 J.
*> NEW FINDING(By mistake!)
11)Now, 8.19*10^-14=mass of beta-particle*velocity(spiritual)
Therefore, velocity(spiritual)=1.89*10^-14/mass of beta-particle.
=(8.19*10^-14*1837*10-1)/(1.6*10^-24)
=9.40314375*10^9 m/s.
Velocity(beta)= 9.7*10^9 m/s.
Velocity(spiritual)=9.4*10^9 m/s.
Velocity(beta)- Velocity(spiritual)=(9.7-9.4)*10^9 m/s.
=3*10^8 m/s.(velocity of light).
12)We know, beta-particles originates from brain(in EEG), through eyes.
Now, 2 beta-particles with velocity 9.7*10^9 m/s must have same energy that of 2 electrons with velocity 3*10^8 m/s.
13)Therefore,
E(beta)=mass of beta-particles *square of (velocity of beta-particles)
=(1.6*10^-24)*square of(9.7*10^9)
1837
=8.19*10^-8 Joules.
E(electron)=9.1*10^-31*square of(3*10^8)*10^6
=8.19*10^-8 Joules.
Hence, 2 beta-particles with velocity 9.7*10^9 m/s serves the purpose of 2 electrons with velocity 3*10^8 m/s.
NUMERICALS:
1)E=M*C^2
=M*C*C
=(2 dim.)+(2dim.)+(2dim.)
=10^2*10^2*10^2
=10^6.
2) Velocity of light=3*10^8 m/s.
=(3*1 dim.)*10^2*10^2*10^2*10^2 m/s.
We get here that, there are 3 dimensions and also a dimension which “touches” all three. May be that is 4th dim.
This shows,10^2 corrosponds to 4th dimension .Hence, 4 times multiplication of 10^2 is done.
Interestingly, by mathematics, 3*1=3 .
3) Similarly,
By power shifting and rewriting equation we have ,
=9*10^9.
This is a new velocity which is more than velocity of light(i.e 9*10^9 m/s).
4)We find, 10^6 times energy of electron equals energy of beta-particle.
10^6 * Energy = Energy
(electron) (beta-particle)
5)Hence, 1) Energy(beta) has beta-particles with velocity 9.7*10^9 m/s
2) It is 10^6 times that of Energy(electrons).
*> We notice that if we add the digits in all powers of 6 , it is divisible by 9 (except 6^1).eg. 6^3=216; (2+1+6=9 which is divisible by 9).
SUBSTITUTION OF X-RAYS IN RADIOLOGY:
1) Planck’s constant, h =4.13*10^-18 kev-sec.
2) E = (4.13*10^-15)*(3*10^8)/1nm (Here, wavelength of electron is taken 1 nm).
=1.2*10^3 ev.
3)Energy(beta)= (6.6*10^-34)*( 9.7*10^9)/wavelength
or, 8.19*10^-8 = (6.6*10^-34)*( 9.7*10^9)/wavelength
or, wavelength= 0.078168498 nm.
4)Diagnostic X-rays have wavelength of 100 nm to 0.01 nm. This wavelength( 0.078168498 nm)lies between the diagnostic range.
5) E=M*C^2
= (8.19*10^-14)/(1.6*10^-19)
= 5.11875*10^5 ev.
6)E =8.19*10^-14 =(6.6*10^-34)*(3*10^8)/wavelength
or, wavelength = 2.417582418*10^-12 meters.
7)E=(4.13*10^-15)*(3*10^8)/(2.41758*10^-12)
=5.125 *10^5 ev.
8)Gamma rays having lesser wavelength in Energy spectrum is used for diagnosing soft tissues like breast(tumours).
TO FIND DENSITY OF UNIVERSE BY DNA DOUBLE HELIX STRUCTURE :
E(proton)/E(electron)=1.44*10^-7/8.19*10^-14=1.7*10^6.
Let us take dimensions of DNA as 34 angstrom and 26 angstrom.
Therefore, Volume of DNA strand = (4/3)*PI*((17 angstrom)^3 –(4 angstrom)^3))
= 2.0301*10^-26 m^3.
We have,
1)1 cooper pair is overlapped by 10^6 cooper pairs.(so, 10^12 electron overlapping)
2) 1 nucleotide has 10^6 cooper pairs.
3) 1 DNA strand has 1 million(or 10^6) nucleotides.
Therefore,
(10^6*10^6*10^6*10^6)*E(beta)*E(proton)/E(electron) =density*( 2.0301*10^-26 )*C^2.
or, (8.19*10^-8) *(1.76*10^6) *10^24= density*( 2.0301*10^-26 )*C^2.
or, 8.19*1.76*10^24 = density*18*10^-10
Density = 8.0* 10^31. Kg/m^3.
We note that this density is “Before” Big -Bang .
After Big-Bang, when universe is formed, density decreases.
Therefore,
Density(universe)=1/(8*10^31)
=1.25*10^-29 g/cm^3 .
*********************** — BAIDYANATH DASH
“ Chewing- gum” Method For Cancer
1)MAKE A GELL OR GUM (LIKE CHEWING-GUM) IN LIQUID STATE AND INSERT IT IN THE CANCEROUS CYST OR TUMOUR.
2)LET IT SOLIDIFY.
3) SURFACE TENSION OR PLASTICITY OF CHEWING-GUM IS HIGH AND SO IT WILL BE IN AN INTACT FORM.
4)THE CANCEROUS CELLS WILL GET ADSORBED ON THE GUM OR IT WILL GET EMBEDDED TO THE CHEWING GUM.
5)INSERT A NANOROBOT OR NANOBOT(HAVING A PUMP AND A MOTOR) WHICH WILL SELECTIVELY PUMP OUT CANCEROUS CELLS WITHOUT LETTING CANCEROUS CELLS TO SPREAD AND WITHOUT DISTURBING OTHER CELLS.
6)ADVANTAGES:
A)CHEWING-GUM IS BIODEGRADABLE AND IS COMPATABLE TO BODY.
B)THE SPREADING OF CELLS IS ZEROED-ON.
C)SIZE OF NANOROBOT IS 10^3 TIMES SMALLER AS COMPARED TO CANCEROUS CELLS.
D)RADIATION-METHOD IS BYPASSED.
***************
BAIDYANATH DASH
A METHOD FOR CALCULATION OF A CODE WRITTEN IN NUMERIC,ALPHABETIC OR ALPHA-NUMERIC:
EXAMPLE 1): CAT MATERIAL
1) WE ASSUME “A” CORROSOPONDS TO 1; “B” TO 2, SO ON.
2) ADD TOTAL NUMBER OF LETTERS PRESENT.IT IS 11.
3) FIND TOTAL IN NUMERICAL.IT IS 103.ADD THE DIGITS. IT IS 1+0+3=4.
4)NOW, ADD 11 TO 4. IT IS 11+4=15.
EXAMPLE 2): 786
1) HERE, ADD (7+8+6)=21.NOW, ADD 2 AND 1.WE GET,2+1=3.
2) HENCE, ADD 3 (NUMBER OF DIGITS IN 786)WITH 3.WE GET, 3+3=6.
EXAMPLE 3): ISBN-81-222-0014-1.
1)HERE, WE GET (9+19+2+14+8+1+2+2+2+0+0+1+4+1)=28.
2)ADD 2 TO 8. WE GET 10. AGAIN ADD 1 TO 0. WE GET 1.
3)NOW, ADD TOTAL LETTERS AND DIGITS IN ALPHANUMERIC GIVEN. IT IS 14. ADD 14 TO 1. WE GET 15.
HOW TO CODE “0’’IN ALPHABETIC?
1)IN CASE THERE IS ZERO(0) PRESENT, IGNORE IT.
FOR EXAMPLE, 2 ZEROS ARE PRESENT IN A SERIES BELOW ,EG.
5500-291.
3) WE, GET NUMBER 55-291.ADD (5+5+2+9+1). WE GET,22.ADD 2 TO 2. WE GET,4.NOW, 4+5=9.
4) ADD 2 (BECAUSE 2 ZEROS) TO 9.WE GET 11.
5) NOTE: 11=9+2.
HOW TO GET MOST APPROXIMATE VALUE ?
Let there be two(2) situations.For example, earlier I had 8 chocolates.I ate 2 chocolates. Now I have 6 .So, There are 2 situations. I ate and now what I have.Hence,according to BODMAS rule,
a)8+6=14
b)8-6=2
c)8/6=1.33333
d)8*6=48
Now,
Most approx. value=(14+2+1.333333+48)/4
=16.25
Hence, we have 14 as the closest value.
CALCULATION BY TIME
Let you get answer as LASER at 6:40 o’clock. Calculate by above method. LASER gives answer as 6. Now, 6:406+4=10.And, 1+3=4.
(Three is added because 6:40 has 3 digits ). Note here that there are 2 situations as finding answer by arithmetic calculation and timing.
So , by BODMAS rule,
a)4+3=7
b)4-3=1
c)4*3=12
d)4/3=1.3333
Hence, most approx. value=(7+1+12+1.3333)/4=5.3333.
We get, 12 as most approximate value.
*********************-BAIDYANATH DASH
HANDY MEDICAL SOFTWARE FOR PATIENTS
1) THERE ARE THREE (3) SECTIONS IN THIS SOFTWARE.
A) PRE DIAGNOSTIC PHASE: A DICTIONARY WHICH INCLUDES NAMES OF ALL DISEASES ALPHABETICALLY.ALSO, DISEASES ARE CATEGORISED INTO THEIR TYPES.LIKE, DIABETES MELITUS, INSIPIDUS,ETC.
B) THE SOFTWARE HAS TO IDENTIFY THE TYPE OF DISEASES.
2) DIAGNOSTIC PHASE : HERE, LEVEL OF THE DISEASE IS MEASURED.
A) THERE IS AN INDICATOR CHART OR GREY SCALE LEVEL WHERE DISEASE IS IDENTIFIED AND DIAGNOSED.LIKE, IF A CANCER IS IN BENIGN OR MELIGNANT STAGE.
B) NOW, THE LEVEL IS MEASURED BY THE SIMPLE EQUATION THAT IT IS PROPORTIONAL TO THE DISEAESE CAUSING ELEMENT.EG.DIABETIC LEVEL IS PROPORTIONAL TO LEVEL OF SUGAR.
3) REMEADY OR TREATMENT PHASE: HERE,EACH DISEASE HAS ITS OWN PHARMACY OR REMEDY.
A) PHARMACY OR THE MEDICINE WILL BE MEASURED BY A SCALE AS TO WHICH QUANTITY TO BE GIVEN.
B) A SOFTWARE WILL SCRUTINIZE THE DISEASE , ITS SYMPTOMS AND ACCORDINGLY PRESCRIBE THE MEDICINE.A CAUTION IS THAT MANY SYMPTOMS MAY BE SIMILAR ; BUT THE SOFTWARE WILL MAKE THE CORRECT MATCH FOR THE PARTICULAR DISEASE.
*****************************
BAIDYANATH DASH
CURRICULAR VITAE
CAREER OBJECTIVE:
To secure a promising position that offers both a challenge and a good opportunity for professional and personal growth.
PERSONAL BIODATA:
Name : Baidyanath Dash
Date of Birth : 1st July, 1982.
Marital status : Single Male.
Father’s Name : Sri. B.K. Dash.
Address : C/o Sri. B.K.Dash, Manager(Vedanta- BALCO), Bidhanbag Unit,West-Bengal,PIN-713337.
Phone no. : 0341-2343678 / 09775313567
e-mail : baidyanath22@gmail.com
EDUCATION:
1)10th std. and 12th std. from C.B.S.E board.
2)Bachelor of Engineering in Medical electronics from Dayananda Sagar college of Engineering, Bangalore.(ISO 9001-2000 Certified)
3) 1 year certificate course on CMIT(Certificate on Medical Imaging Technology).
4)Two months work experience certificate .
RELATED SKILLS:
Hardware: Microprocessor, Microcontroller, Analog Design, Digital Design.
Design Tools: Oscilloscopes, Function generator, Digital Multimeters, logic analysers.
Computer Skills: MS Office, Excel, C, C++, Internet.
Softwares: MATLAB, Digital Signal Processing, Digital Image Processing.
LANGUAGE:
Fluent in English, Hindi, Bengali, Oriya.
PROJECT:
Microcontroller based Diabetic-Foot Sensor Device.
Description:The thermal sensitivity of a diabetic foot is mapped by providing thermal stimuli by heater probe and getting patient’s reaction in form of pressing response button.Microcontroller is programmed and foot pedal switches is provided to start true and false alarm.LCD screen displays probe temperature.
EXPERIENCE:
1) I have experience to maintain and operate instruments .
2) Worked in a diagnostic center .
HOBBIES:
a) Internet surfing
b) Travelling
ACTIVE PARTICIPATIONS:
1)Written a paper titled “Relation between DNA and Cooper pairs for a call of paper at an International Conference at Singapore .”
2)Attended a National level and a state level seminar on Recent advancements in Biomedical Devices at Bangalore.
3)Attended an International Conference on Scientific Validation and Technical Evaluation of Ancient Medical systems.
4)Written a method to calculate a code written in numerical, alphabetical and alphanumerical.
DECLARATION:
I, Baidyanath Dash, hereby declare that the above information is true to best of my knowledge.
With Regards,
Thanking You, Date:
Yours Sincerely, Place:BidhanbagUnit.
Baidyanath Dash.
(B.E: Medical Electronics)
AUTOMATED HEALTHCARE MACHINES :
1) AN ELECTRONIC MACHINE LIKE AN ATM , WILL HAVE THE FACILITY TO INSERT A CARD.
2) THE BLOOD SAMPLE IS PLACED AT THE CENTER OF THE CARD.IT MAY BE BY A COMPOUNDER
OR A PRACTIONER WHO WILL DO IT OR WE CAN DO IT OURSELF.A SMALL ‘PRICK’ WILL BE PROVIDED WITH CARD.
3) PATIENTS WILL BE PROVIDED WITH THIS CARD .IT WILL BE THEN INSERTED INTO MACHINE.
4) THE MACHINE WILL HAVE THE ELECTRONIC SENSORS WHICH WILL IDENTIFY THE DISEASE.
5) THE MACHINE IS RUN BY A COMPUTER. A SOFTWARE WHICH WILL HAVE THE FACILITY TO IDENTIFY DISEASE,CATEGORISE IT AND TO IDENTIFY ITS LEVEL OF PRESENCE IS THE SOUL OF THIS PROJECT.IT MAY BE AS FOLLOWS:
6) HANDY MEDICAL SOFTWARE FOR PATIENTS
7) THERE ARE THREE (3) SECTIONS IN THIS SOFTWARE.
A) PRE DIAGNOSTIC PHASE: A DICTIONARY WHICH INCLUDES NAMES OF ALL DISEASES ALPHABETICALLY.ALSO, DISEASES ARE CATEGORISED INTO THEIR TYPES.LIKE, DIABETES MELITUS, INSIPIDUS,ETC.
9) B) THE SOFTWARE HAS TO IDENTIFY THE TYPE OF DISEASES.
10)
11) 2) DIAGNOSTIC PHASE : HERE, LEVEL OF THE DISEASE IS MEASURED.
12) A) THERE IS AN INDICATOR CHART OR GREY SCALE LEVEL WHERE DISEASE IS IDENTIFIED AND DIAGNOSED.LIKE, IF A CANCER IS IN BENIGN OR MELIGNANT STAGE.
13) B) NOW, THE LEVEL IS MEASURED BY THE SIMPLE EQUATION THAT IT IS PROPORTIONAL TO THE DISEAESE CAUSING ELEMENT.EG.DIABETIC LEVEL IS PROPORTIONAL TO LEVEL OF SUGAR.
14) 3) REMEADY OR TREATMENT PHASE: HERE,EACH DISEASE HAS ITS OWN PHARMACY OR REMEDY.
15) A) PHARMACY OR THE MEDICINE WILL BE MEASURED BY A SCALE AS TO WHICH QUANTITY TO BE GIVEN.
16) B) A SOFTWARE WILL SCRUTINIZE THE DISEASE , ITS SYMPTOMS AND ACCORDINGLY PRESCRIBE THE MEDICINE.A CAUTION IS THAT MANY SYMPTOMS MAY BE SIMILAR ; BUT THE SOFTWARE WILL MAKE THE CORRECT MATCH FOR THE PARTICULAR DISEASE.
17) THE SOFTWARE WILL HAVE FACILITY TO INSERT NEW NAMES OF MEDICINES
AVAILABLE AND REPLACE WHICH IS OUTDATED.
18) THE CARD IS EASY TO HANDLE AND CAN BE MADE AVAILABLE AT ANY MEDICINE STORE OR
HEALTHCARE SYSTEM.
19)ADVANTAGES :
A)EASY AVAILIBILITY.
B)CAN BE CARRIED ANYWHERE.CAN BE YOUR SAVIOUR IN EMERGENCY.
C)TIME TAKEN TO GET INFORMATION IS MUCH SHORTER.
D)LIKE THIS CARD(AS AN ATM), WE CAN OPEN “HEALTH ATMS” IN OUR PLACE.NOT ONLY BLOOD, ANY SAMPLE CAN BE TESTED IN THIS MACHINE.
*********************
-BAIDYANATH DASH
SOLAR BOOTS
1. THE SPORTS SHOES WE WEAR CAN BE MADE OF SILICON WAFERS HAVING NANO SOLAR CELLS. TODAY, A PAINT IS AVAILABLE TO PAINT THE BOOT WITH SOLAR CELLS.
2. SOCKS ALSO WILL BE MADE OF SAME THING WITH NANOTECHNOLOGY.
3.SOLAR ENERGY IS TRAPPED IN THE CELLS TO CARRY ON BODY’S CHEMICAL REACTION.
4.THE LACTIC ACID PRODUCED DURING EXERCISE OR DURING SPORTS WILL BE CONVERTED INTO LACTOSE, WHICH IS A VERY GOOD SOURCE OF ENERGY.
5.AN ENZYME WILL HELP IN THE CONVERSION.
ADVANTAGES:
1.SOLAR ENERGY IS CLEAN,NATURAL,AND ULTIMATE SOURCE OF ENERGY.
2.NO EXTERNAL ENERGY SOURCE IS REQUIRED AS WE GET ENERGY FROM LACTOSE.
3.THE BODY GETS FREE FROM LACTIC ACID,&SIMULTANEOUSLY WE GET ENERGY.ALSO, FATIGUE OF BODY IS MINIMIZED.
Dear Madam,I am too happy for your support .Kindly, can you please send a mail to me so that I get more encouragement and support .
Thank You,
With Regards,
Baidyanath
This blog today attains 1(one) year.Congrats to all those who visit blisstree.com
THINGS TO PONDER
1.WE HAVE 26 LETTERS IN ENGLISH.
2.IN HINDI, THERE ARE 33.
3.WE OBSERVE THAT ” KA, KHA, GA, GHA…”.HERE,H LETTER IS PRONOUNCED 8 TIMES.
4.IF WE ADD ONE “H” LETTER IN HINDI,AND;TAKE OUT “KHA,GHA..” WHICH HAS “H”, WE WILL HAVE(33-8+1)=26 LETTERS IN HINDI TOO!
THE ABOVE WRITING”THINGS TO PONDER” IS NOT “APPLICABLE” AS WE CANNOT BUILD WORDS.
dear madam, can you kindly tell how many of these writings are “new and applicable and will add new feather on our cap”?
thank you, madam
I WANT TO SEND MY PHOTO.HOW WILL I SEND?
EARTH-LIKE ENVIRONMENT ON ANOTHER PLANET
1)A SATELLITE (WITH OWN ENERGY SOURCE) ,GEOSYNCHRONOUS TO PLANET WILL REVOLVE AROUND THE PLANET. WE REQUIRE TO PROVIDE SAME ENERGY TO ALL PLANETS. A REACTOR MAY FUNCTION TO GENERATE THE ENERGY. ENERGY PRODUCTION IS BASED ON TWO CONDITIONS –
A)DISTANCE FROM SUN.(FARTHER PLANETS WILL REQUIRE MORE ENERGY)
B)SIZE OF PLANET.(BIGGER PLANET WILL REQUIRE MORE ENERGY)
THAT IS, DISTANCE AND SIZE ARE TWO FACTORS.
2)WE WILL GENERATE OXYGEN BY ARTIFICIAL PHOTOSYNTHESIS. ARTIFICIAL-LEAF WILL HELP IN THE PROCESS.IT WILL ABSORB LIGHT, HEAT AND WATER AND WILL PRODUCE OXYGEN.
3)WE WILL GET WATER BY MELTING ICE BY THE REACTORS.ALSO FROM UNDERGROUND SOURCES.
4)FOR A PROTECTION LAYER, WE HAVE TO “WEAVE” THE ARTIFICIAL LEAF AROUND THE PLANET.THIS WILL SUBSTITUTE THE OZONE LAYER AND HAS DUAL FUNCTIONS:
A)TO PROTECT PLANET FROM RADIATION.
B)TO GENERATE OXYGEN BY ABSORBING WATER VAPOUR, LIGHT AND HEAT RADIATED FROM PLANET.
5)THE DRONES GEOSTATIONED AROUND THE PLANET WILL HELP IN WEAVING THE LEAF.THE CHLOROPHYLL PIGMENT WILL BE EMBEDDED AT THE BOTTOM SIDE OF THE LEAF WHICH IS LIGHTER IN COLOUR.
6)THE CHLOROPHYLL WILL GENERATE OXYGEN. THE ARTIFICIAL BEES/SPIDERS WILL “WEAVE” THE LEAF, MOVING FROM ONE DRONE TO ANOTHER, SIMILAR TO WEAVING HANDLOOM OR CARPET . IT MAY TAKE AROUND 25 YEARS,DAY AND NIGHT. A BUCKY-BALL SHAPED STRUCTURE WILL BE FORMED, AS A SPHERICAL SHAPE IS DIFFICULT TO OBTAIN.
7)LIGHT FROM THE SOURCE WILL FALL ON THE ARTIFICIAL-LEAF,PENETRATE TO STRIKE THE SURFACE OF THE PLANET,GETS PARTIALLY REFLECTED BACK TO BE ABSORBED BY THE LEAF LAYER.NATURALLY,THE SPEED OF REFLECTED LIGHT IS REDUCED AND CAN BE EASILY ABSORBED BY CHLOROPHYLL PIGMENTS AND THE ATMOSPHERE WILL GET OXYGEN IN RETURN.PLANTATION OF THIS ARTIFICIAL PLANTS WILL TAKE LONGER TIME TO TO GET OXYGEN IN ATMOSPHERE.
*******************************
-BAIDYANATH DASH
LOCATION TRACER:
1.WE HAVE THE TARGET TO IDENTIFY THE EXACT LOCATION OF ANY INCIDENCE.
2.WE WILL DEVELOP A METHOD WHICH WILL SERVE THE PURPOSE.THE METHOD IS BY USING SUMLIGHT/MOONLIGHT ON A PIECE OF A PLAIN PAPER.
3.WE KNOW THAT RADIUS OF EARTH IS ABOUT 65,000 KM.FIRST WE MAKE THE SCALE.
SCALE: 1CENTIMETER=100 KILOMETERS(6.5*2=13).
4.NOW, WE HAVE TO DRAW A CIRCLE ON THE PLAIN PAPER OF RADIUS 13 CM. IF WE TAKE RADIUS 10 CM,SCALE IS 1 CM EQUALS 130 CM.
5.TAKING A COMPASS/ROUNDER AND PLACING AT THE CENTER , O AND A POINT ON CIRCUMFERENCE, WE DRAW THE LINE SEGMENT ALONG THE SHADOW FROM THE CENTER TIP TO CENTER OF CIRCLE AND OTHER TO THE POINT ON CIRCUMFERENCE.LET US MARK THE TWO POINTS WHICH CUT THE CIRCUMFERENCE.NAME IT A AND B.WE GET A CHORD,A TO B.
6.SIMILARLY,TAKING A POINT EXACTLY OPPOSITE TO THE POINT ON CIRCUMFERENCE(OPPOSITE ALONG DIAMETER),WE DRAW LINES ALONG SHADOW.
7.NOW, LET US TAKE AN ARBITRARY POINT P INSIDE CIRCLE.WE DO NOT KNOW THE DISTANCE FROM CENTER.DRAW A LINE SEGMENT FROM THIS POINT TO CENTER.
7.COMPARING TO EARTH SURFACE, THE CHORD AB IS NEGLIGIBLE/TOO SMALL WHICH WE CAN ASSUME AS A FLAT SURFACE OR LINE SEGMENT AB.
8.WE NOW FIND THE DEVIATION D.THE MATHEMATICAL EQUATION IS
DEVIATION D =AB*OP/ (2*PI*R)
9.TAKING THE RADIUS OF DEVIATION,MAKE A CIRCLE WITH DOTTED LINES INSIDE THE CIRCLE.
10.PLACE COMPASS AT MEETING POINT OF OP AND THE DOTTED CIRCLE AND AT P AND DRAW THE LINES ALONG SHADOW.THE TIP OF COMPASS WHERE IT CUTS THE DOTTED CIRCLE IS THE EXACT LOCATION OF INCIDENCE.
ADVANTAGES:
1.WE CAN TRACE THE LOCATION INSIDE A PLACE WHERE IT IS DIFFICULT TO REACH.
2.THIS METHOD IS INDIVIDUAL SPECIFIC.
3.EASY TO HANDLE.
4.NO ELECTRONICS IS /HI-TECH IS USED WHICH NEED MAINTAINANCE AND REPAIR.
5.WE CAN USE FURTHER METHODS AS CODE DETECTION AND APPROXIMATION METHOD TO LOCATE.
**************************************
-BAIDYANATH DASH
THE ABOVE METHOD NEEDS FURTHER MODIFICATION AND PROOF-READING.
NOTE:1)TAKING THE RADIUS OF DEVIATION,MAKE A CIRCLE WITH DOTTED LINES INSIDE THE CIRCLE.
PLACE COMPASS AT MEETING POINT OF OP AND THE DOTTED CIRCLE AND AT P AND DRAW THE LINES ALONG SHADOW.
IN ABOVE WE HAVE TO SEE IF WE HAVE TO PLACE COMPASS A MEETING POINT OF OP AND THE DOTTED CIRCLE “AND AT CENTER”.(NOT AT P)
LOCATION TRACER:
TWO IMPORTANT THINGS TO BE NOTED:
1)IF (*AB) IS GREATER THAN 2*PI*R,
DEVIATION ,D= (OP*AB)/2*PI*R,
ELSE,
D=(2*PI*R)/(OP*AB).
2)IF SHADOW OF COMPASS IS BIGGER THAN CIRCLE,TAKE SUITTABLE SCALE IN RATIO OF 6.5.IN MORNING AND EVENING TIMES, SHADOW IS BIGGER.
3) IF POSSIBLE, CIRCLE MUST BE DRAWN KEEPING SIZE OF COMPASS IN MIND.
4) IF SHADOW IS BIGGER THAN INNER DOTTED CIRCLE, TAKE THE TIP OF COMPASS TO CIRCUMFERENCE AND DRAWFROM CIRCUMFERENCE TO THE CENTER OF INNER CIRCLE.
***********************************
-BAIDYANATH DASH
RECTIFICATION:
IF (OP*AB) IS GREATER THAN 2*PI*R,
DEVIATION ,D= (OP*AB)/2*PI*R,
ELSE,
D=(2*PI*R)/(OP*AB).
EARTH-LIKE ENVIRONMENT ON ANOTHER PLANET
1)A SATELLITE (WITH OWN ENERGY SOURCE) ,GEOSYNCHRONOUS TO PLANET WILL REVOLVE AROUND THE PLANET. WE REQUIRE TO PROVIDE SAME ENERGY TO ALL PLANETS. A REACTOR MAY FUNCTION TO GENERATE THE ENERGY. ENERGY PRODUCTION IS BASED ON TWO CONDITIONS –
A)DISTANCE FROM SUN.(FARTHER PLANETS WILL REQUIRE MORE ENERGY)
B)SIZE OF PLANET.(BIGGER PLANET WILL REQUIRE MORE ENERGY)
THAT IS, DISTANCE AND SIZE ARE TWO FACTORS.
2)WE WILL GENERATE OXYGEN BY ARTIFICIAL PHOTOSYNTHESIS. ARTIFICIAL-LEAF WILL HELP IN THE PROCESS.IT WILL ABSORB LIGHT, HEAT AND WATER AND WILL PRODUCE OXYGEN.
3)WE WILL GET WATER BY MELTING ICE BY THE REACTORS.ALSO FROM UNDERGROUND SOURCES.
4)FOR A PROTECTION LAYER, WE HAVE TO “WEAVE” THE ARTIFICIAL LEAF AROUND THE PLANET.THIS WILL SUBSTITUTE THE OZONE LAYER AND HAS DUAL FUNCTIONS:
A)TO PROTECT PLANET FROM RADIATION.
B)TO GENERATE OXYGEN BY ABSORBING WATER VAPOUR, LIGHT AND HEAT RADIATED FROM PLANET.
5)THE DRONES GEOSTATIONED AROUND THE PLANET WILL HELP IN WEAVING THE LEAF.THE CHLOROPHYLL PIGMENT WILL BE EMBEDDED AT THE BOTTOM SIDE OF THE LEAF WHICH IS LIGHTER IN COLOUR.
6)THE CHLOROPHYLL WILL GENERATE OXYGEN. THE ARTIFICIAL BEES/SPIDERS WILL “WEAVE” THE LEAF, MOVING FROM ONE DRONE TO ANOTHER, SIMILAR TO WEAVING HANDLOOM OR CARPET . IT MAY TAKE AROUND 25 YEARS,DAY AND NIGHT. A BUCKY-BALL SHAPED STRUCTURE WILL BE FORMED, AS A SPHERICAL SHAPE IS DIFFICULT TO OBTAIN.
7)LIGHT FROM THE SOURCE WILL FALL ON THE ARTIFICIAL-LEAF,PENETRATE TO STRIKE THE SURFACE OF THE PLANET,GETS PARTIALLY REFLECTED BACK TO BE ABSORBED BY THE LEAF LAYER.NATURALLY,THE SPEED OF REFLECTED LIGHT IS REDUCED AND CAN BE EASILY ABSORBED BY CHLOROPHYLL PIGMENTS AND THE ATMOSPHERE WILL GET OXYGEN IN RETURN.PLANTATION OF THIS ARTIFICIAL PLANTS WILL TAKE LONGER TIME TO TO GET OXYGEN IN ATMOSPHERE.
*******************************
-BAIDYANATH DASH