Dr. Anita Goel – Studying DNA Using Physics
Anita Goel, MD, PhD, is another example of a polymath who is able to combine seemingly disparate disciplines to understand natural phenomena – physics and genetics. Named one of the world’s 35 most promising researchers under the age of 35 by MIT’s Technology Review Magazine, Dr. Goel of Harvard University is studying how DNA polymerase replicates DNA.
“There’s this sense of wonder, with a lot of nature around you,” Goel said. “We understand so much about atoms and molecules, but do we really understand the basic physics of life?”
Dr. Goel likens DNA polymerase to a nanoscale motor that converts chemical energy into mechanical energy as it moves along a strand of DNA. In addition to studying DNA replication, she is developing new methods for detecting viruses and bacteria with potential use in counter-terrorism. This work is performed with her company, Nanobiosym.
Harvard University Gazette, December 8, 2005
A MATHEMETICS SERIES FORMULA:
1)IF A TWO DIGIT NUMBER ENDS WITH 9, WE GET THE SAME ON MULTIPLYING AND ADDING THE TWO INDIVIDUAL DIGITS.
EX. WE TAKE 59(5*9=45,5+9=14,14+45=59).
INTERESTINGLY,RAT IS CODED AS 5 AND CAT AS 9. CAT EATS RAT.
2)IF A TWO DIGIT NUMBER STARTS WITH 9, WE GET OPPOSITE (59 AS 95)ON MULTIPLYING AND ADDING THE TWO INDIVIDUAL DIGITS.
EX. WE TAKE 97(9+7=16,9*7=63,63+16=79).
********-BAIDYANATH DASH
LIE DETECTOR:
A)”TIME” IS CODED AS 6.
B)”TRUE” IS CODED AS 9.
C)”FALSE IS CODED AS 12.
D)IF THE QUESTION IS :WHICH IS NEARER TO GALL-BLADDER?
1)LIVER OR 2)STOMACH?
E)”LIVER” IS CODED AS 6.”STOMACH” IS CODED AS 14.
F)ANSWER IS LIVER.IT IS A TRUE ANSWER,IF WE SELECT LIVER.OTHERWISE,IT IS FALSE.
G)ANOTHER QUESTION: WHICH IS NEARER TO KOLKATA?
OPTIONS:1)CHENNAI OR 2)BHOPAL?
H)”CHENNAI ” IS CODED AS 16. “BHOPAL” IS CODED AS 15.
I)ANSWER IS BHOPAL AS IT IS NEARER TO 6(TIME).TRUE(9) IS NEAR TO TIME(6).
J)ANOTHER QUESTION: WHO IS KNOWN AS LITTLE MASTER?
OPTIONS: 1)SACHIN RAMESH TENDULKAR OR 2)SHAH RUKH KHAN?
K)”SACHIN RAMESH TENDULKAR” IS CODED 28. “SHAH RUKH KHAN ” IS CODED 15.
L)IF WE SELECT SACHIN,ANSWER IS TRUE AS WE KNOW,FROM 786( PIOUS NUMBER),7+8+6=21=>2+1=>3+3=6(CODED FOR TIME).
M)ALSO,WE NOTE THAT “LITTLE MASTER” IS CODED 13 WHICH IS DIFFERENCE BETWEEN CODE OF SACHIN AND SRK . IE.28-15=13.
****-BAIDYANATH DASH
LIE DETECTOR:
1)WITH THIS METHOD,WE CAN AVOID ANY NARCO TESTS OR ELECTRONIC COMPONENTS.
2)THIS IS EASY AND VERY SIMPLE AND GIVES 100% RESULT.
3)WE ALSO USE NEAR APPROXIMATION METHOD TO GET THE CORRECT NUMBER(MAY BE ALSO FOR REJECTING THE OPTIONS ).
4)THESE METHODS CAN ALSO BE USED IN COMPETETIVE EXAMS (OBJECTINE QUESTIONS).
LIE DETECTOR:
SOME MORE EXAMPLES:
1)QUESTION:WHO IS A CRICKET PLAYER?
A)RAHUL DRAVID B)HRITIK ROSHAN C)SRK D)JASPAL RANA?
ANSWER: A)RAHUL IS CODED 12.
B)HRITIK IS CODED 18.
C)SRK IS CODED 15.
D)JASPAL RANA IS CODED 13.
HENCE, A) RAHUL DRAVID IS CORRECT OPTION.
NOTE: WE SHOULD AVOID ABBRIVIATED FORM OF WORDS.
*******–BAIDYANATH DASH
LIE DETECTOR:
SOME MORE EXAMPLES:
1)QUESTION:WHO IS A CRICKET PLAYER?
A)RAHUL DRAVID B)HRITIK ROSHAN C)SRK D)JASPAL RANA?
ANSWER: A)RAHUL IS CODED 12.(NEAR TO TIME CODE(IE. 6)
B)HRITIK IS CODED 18.
C)SRK IS CODED 15.
D)JASPAL RANA IS CODED 13.
HENCE, A) RAHUL DRAVID IS CORRECT OPTION.
NOTE: WE SHOULD AVOID ABBRIVIATED FORM OF WORDS.
*******–BAIDYANATH DASH
APPLICATION OF CODE SELECTION METHOD(LIE DETECTOR):
RULES FOR THIS METHOD:
1)THE HIGHEST CODE NUMBER OF GIVEN OPTIONS IS GIVEN LAST PRIORITY.
2)WE THEN SELECT THE CODE NEAREST TO TIME CODE(IE. 6).
3)WE CHECK THE OPTIONS FOR TRUE(5) OR FALSE(12).WE NOTICE HERE , ADDITION IN “TRUE “IS LESS THAN “FALSE” AND CODE IS ALSO LESS(5<12).HENCE,SIMILARLY OPTIONS ARE SELECTED.
EXAMPLES:
QUESTION:
1)WHICH IS THE STUDY OF EXCEPTION?
A)BIOLOGY B)PHYSICS C)CHEMISTRY D)MATHEMATICS
ANSWER: A)BIOLOGY
2)WHICH GIVES MILK TO MAN?
A)COW B)RAT C)BAT D)CAT
ANSWER: A)COW
NOTE: IN ABOVE QUESTION,
A)WE GIVE CAT(CODE 9) AS LAST PRIORITY.
B)THEN WE SELECT RAT(CODE 5), NEARER TO CODE 6.
C)FOR THIRD CONDITION TO FULFILL, WE NOTICE THAT BOTH COW AND BAT HAVE CODE 8. ALSO,RAT(CODE 5) " DOES NOT " FULFILL THIRD CONDITION.BETWEEN COW AND BAT, COW IS APPROPRIATE ANSWER AS IT FULFILLS ALL THREE CONDITIONS.
3)WHO IS AN ACTOR?
A)SRK B)RAHUL DRAVID C)SACHIN TENDULKAR D)BAIDYANATH DASH
ANSWER: A)SRK
NOTE: A) WE GIVE SACHIN (CODE 28) LAST PRIORITY.
B)WE SELECT RAHUL(NEAREST TO CODE 6).
C)BETWEEN SRK(CODE 15) AND BAIDYANATH DASH(CODE 14),BAIDYANATH DOES NOT FULFILLS THIRD CONDITION.AND BETWEEN RAHUL AND SRK, THEY FULFILL THE THIRD CONDITION AS FALSE AND TRUE,IE, SRK IS TRUE AND RAHUL IS FALSE.
***************–BAIDYANATH DASH
COOPER PAIR IMAGING TECHNOLOGY:
1) A LONG CUBOID BOX IS COVERED BY PLASTIC OR GLASS.
2)AN EXHAUST FAN FOR AIR INFLUX IS NEAR THE HEAD.
3)THE COOPER PAIR IMAGING IS BASED ON PRINCIPLE THAT BODY WHICH CONTAINS 83% WATER (H2O MOLECULE) WHICH CONTAINS A LONE PAIR ELECTRON ON OXYGEN MOLECULE.
4)THEY MAY BE COOPER PAIRS . THEY EMIT GAMMA RADIATION DUE TO SPIN.
5)BY DETECTING THE EMISSION IN NORMAL AND AFFECTED REGIONS OF BODY BY SPECTROSCOE,WE CAN GET IMAGE ON PHOTOGRAPHIC PLATES.
COOPER PAIR IMAGING TECHNOLOGY:
6)WE WILL USE SQUIDS(SUPERCONDUCTING MATERIALS THROUGH WHICH COOPER PAIRS FLOWS).
7)WE ALSO CAN BRING COOPER -PAIRS TOGETHER.
8)THE 2 SUPERCONDUCTING MAGNETS ARE PLACED PARALLEL TO EACH OTHER AND PATIENT
AT THE CEN
9)THIS WILL ALIGN COOPER PAIRS AND WILL BE EASIER FOR IMAGING.
–BAIDYANATH DASH
A RECTIFICATION:
CODE OF BAIDYANATH IS 23 NOT 14.
WE SEE MORE EXAMPLES:
A)WHO EATS GRASS?
A)COW B)RAT C)BAT D)CAT?
ANSWER:CODES: COW(8),RAT(5),CAT(9),BAT(8).
A)ACCORDING TO FIRST CONDITION,WE HAVE CAT LAST PRIORITY.
B)RAT IS NEAREST TO 6.WE THEN COMPARE RAT WITH COW AND BAT.WE HAVE COW AND RAT AS SIMILAR TO TRUE AND FALSE.WE NOTICE HERE THAT CODE OF RAT IS SAME AS CODE OF “TRUE”IE. 5.
C)ACCORDING TO THIRD CONDITION,WE HAVE RAT AS TRUE AND COW AS FALSE, BUT, WE NOTE HERE THAT RAT IS A “PERFECT TRUE”, WHICH IS NOT VIABLE.
HENCE, COW IS CORRECT OPTION.
***-BAIDYANATH DASH
MORE EXAMPLES:
1)QUESTION: WHICH IS SOLID?
A)ICE B)WATER?
ANSWER:CODES:ICE(11) AND WATER (9).
A)ACCORDING TO FIRST CONDITION,WE HAVE ICE LAST PRIORITY.
B)WATER IS NEAREST TO 6.
C)THEY DO NOT SATISFY THIRD CONDITION. HENCE,ICE IS NOT SIMILAR TO TRUE AND WATER IS NOT SIMILAR TO FALSE.HENCE,WATER IS REJECTED. HENCE ,ICE IS ANSWER.
MORE EXAMPLES:
QUESTION: WHICH COLOUR COMES IN POSITION 5 IN “VIBGYOR” ?
A)VIOLET B)RED C)YELLOW D)BLUE?
ANSWER:CODES:VIOLET(8),RED(7),YELLOW(8),BLUE(8).
A)ACCORDING TO FIRST CONDITION,WE HAVE VIOLET,YELLOW AND BLUE AS LAST PRIORITY.
B)RED IS NEAREST TO 6.WE THEN COMPARE IT WITH ALL THREE.THE EXTREMES AS TRUE AND FALSE ARE RED AND YELLOW.
C)ACCORDING TO THIRD CONDITION, RED AND YELLOW ARE SIMILAR TO TRUE AND FALSE.HERE ,WE NOTE THAT DIFFERENCE BETWEEN CODES OF “VIBGYOR AND YELLOW” IS 15-8=7.THIS IS CODE OF RED . HENCE,YELLOW IS ANSWER.HENCE,WE ALSO HAVE TO KEEP IN MIND TO TAKE DIFFERENCE BETWEEN QUESTION AND AN OPTION LEFT.
*********–BAIDYANATH DASH
A RECTIFICATION:
SHAH RUKH KHAN IS CODED AS 14, AND NOT 15 AS STATED EARLIER.
ANOTHER QUESTION: WHICH IS CALLED AS “PARADISE ON EARTH”?
A)JAMMU AND KASHMIR B)ODISHA C)NAGALAND D)BIHAR
ANSWER:CODES:
JAMMU AND KASHMIR(156) ,CODE IS 18.
ODISHA(56),CODE IS 8.
NAGALAND(54),CODE IS 17.
BIHAR(38),CODE IS 7.
A)ACCORDING TO FIRST CONDITION,J&K IS LAST PRIORITY.
B)ACCORDING TO SECOND,BIHAR IS NEAREST TO 6.IT IS TO BE COMPARED WITH ODISHA AND NAGALAND.AS CODE OF NAGALAND(54) AND ODISHA (56) DOES NOT MATCH FOR “FALSE”,
WE NEGLECT ODISHA AS COMPARED TO BIHAR AS SIMILAR TO “TRUE”.
C)NOW WE HAVE BIHAR AND J&K AS SIMILAR TO TRUE AND FALSE .BUT, THIS IS AN EXCEPTION AS WE KNOW J&K IS THE ANSWER.WE OBSERVE THAT ADDITION OF “PARADISE ON EARTH ” IS 16.WE NOTICE A SIMPLE EQUATION:1,2,3,4,5,6,7,8,9.
1+2+3+4+5=15(1+5=6),THEN COMES 6 IN SEQUENCE AND ,7+8+9=24(2+4=6).
NOW,16-7=9;18-16=2,24-15=9,8+7=15;AND 16,17,18 IS A SEQUENCE.HENCE,THIS QUESTION IS AN EXCEPTION.
A RECTIFICATION: CODE FOR RAT IS 6 ,AND NOT 5.
SOME MORE EXAMPLES:
QUESTION:FIND ODD OPTION OUT.
A)RAT B)CAT C)BAT D)MAT
ANSWER: CODES:RAT(6),CAT(9),BAT(8),MAT(10).
A)ACCORDING TO FIRST CONDITION,MAT IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,RAT IS NEAREST TO 6.WE HAVE TO COMPARE BETWEEN
RAT AND CAT, AS BAT IS REJECTED.
C)ACCORDING TO THIRD OPTION,THEY DO NOT FOLLOW “TRUE AND FALSE CONDITION.HENCE,MAT IS TRUE AND RAT IS FALSE HERE.SO,MAT IS ODD OPTION.
*********–BAIDYANATH DASH
RULES AND CONDITIONS:
RULES FOR THIS METHOD:
1)THE HIGHEST CODE NUMBER OF GIVEN OPTIONS IS GIVEN LAST PRIORITY.
2)WE THEN SELECT THE CODE NEAREST TO TIME CODE(IE. 6).
3)WE CHECK THE OPTIONS FOR TRUE(5) OR FALSE(12).WE NOTICE HERE , ADDITION IN “TRUE “IS LESS THAN “FALSE” AND CODE IS ALSO LESS(5<12).HENCE,SIMILARLY OPTIONS ARE SELECTED.
4)IN CASE WE DO NOT FIND A SOLUTION,WE SUBTRACT THE CODE OF QUESTION ASKED TO OPTIONS GIVEN.
5)"PARADISE ON EARTH "PROBLEM IS AN EXCEPTION AND A CLASSIC PROBLEM.
AUTOMATIC LASER GUNS:
CONSTRUCTION:
1)A MINIATURE Nd-YAG LASER TO BE INSERTED INTO BODY OF GUN.
2)THE GUN HAS 3 SECTIONS:
A)LASER GENERATION B)SIMULATED OR PULSATED EMISSION C) OUTPUT PIPE
3)ON A TRIGGER BUTTON, THE GENERATION OF LASER STARTS.
4)THE SIMULATED OR PULSATED EMISSION SECTION HAS CAPACITORS.
5)A PIPE MADE OF TUNGSTEN(OPTICAL FIBRES MAY BE USED WHICH MAY BE EMBEDDED IN TUNGSTEN MATRIX ).
6)TUNGSTEN IS CHOSEN AS THE LIGHT IS HEATED AND AMPLIFIED.
7)AN APERTURE(LIKE CAMERA) TO SELECT THE OPTICAL FIBRES WHICH IS OPENING OF EMISSION OF LASER BEAM.
***************
–BAIDYANATH DASH
MORE QUESTIONS:
QUESTION: WHAT IS COMBINATION OF SMOKE AND FOG CALLED?
A)SMOKIN B)FOGGY C)SMOG D) ACID-RAIN?
ANSWER: CODES:SMOKIN(15),FOGGY(11),SMOG(13),ACID-RAIN(13).
A)ACCORDING TO FIRST CONDITION,SMOKIN IS LAST PRIORITY.
B)FOGGY IS NEAREST TO 6.WE NOW COMPARE FOGGY WITH SMOG AND ACID-RAIN.WE HAVE NOW
FOGGY AND SMOG.
C)ACCORDING TO THIRD CONDITION, THIS DOES NOT SATISFY TRUE AND FALSE.HENCE,SMOG IS ANSWER.
MORE QUESTIONS:
QUESTION:WHERE IS TAJ-MAHAL?
A)AMBALA B)DWARKA C)PURI D)AGRA?
ANSWER:CODES:AMBALA(9),DWARKA(10),PURI(5),AGRA(13).
A)ACCORDING TO FIRST CONDITION,AGRA IS LAST PRIORITY.
B)ACCORDING TO SECOND, PURI IS NEAREST TO 6.WE NOW COMPARE PURI WITH AMBALA AND
DWARKA.AMBALA IS REJECTED.WITH AGRA AND DWARKA,LATTER IS REJECTED AS IT DOES NOT SATISFY FALSE CONDITION.
C)ACCORDING TO THIRD CONDITION,PURI AND AGRA SHOWS THE “RULE 5″ TYPE QUESTION.NOTE THAT THIS PROBLEM EXISTS WITH HIGHEST CODE ONLY.WE FIND CODE OF TAJ-MAHAL AS 11.NOW,11-5=6;24-11=13.
HENCE AGRA IS ANSWER.
MORE EXAMPLE:
QUESTION:WHERE IS LORD JAGANNATH TEMPLE LOCATED?
A)GUJRAT B)KERALA C)KARNATAKA D)ODISHA?
ANSWER:CODES:GUJRAT(11),KERALA(13),KARNATAKA(15),ODISHA(8).
A)ACCORDING TO FIRST CONDITION,KARNATAKA IS LAST PRIORITY.
B) ODISHA IS NEAREST TO 6. COMPARING BETWEEN GUJRAT , KERALA AND ODISHA;GUJRAT IS REJECTED.BETWEEN KERALA AND KARNATAKA ,KERALA IS REJECTED.WE ARE LEFT WITH ODISHA AND KARNATAKA.
C)THIS SATISFIES TRUE AND FALSE CONDITION. HENCE,ODISHA IS ANSWER.
A MAJOR RECTIFICATION:
1)WE HAVE “TRUE”(64=>6+4=10=>1+4=5) AN “FALSE”(43=>4+3=7,7+5=12).WE NOTICE THAT,
SUMMATION(64) IN TRUE IS MORE THAN THAT IN FALSE(43). BUT, CODE OF TRUE IS LESS THAN FALSE.
QUESTION: MORE EXAMPLE:
QUESTION:WHERE IS LORD JAGANNATH TEMPLE LOCATED?
A)GUJRAT B)KERALA C)KARNATAKA D)ODISHA?
ANSWER:CODES:GUJRAT(11),KERALA(13),KARNATAKA(15),ODISHA(8).
A)ACCORDING TO FIRST CONDITION,KARNATAKA IS LAST PRIORITY.
B) ODISHA IS NEAREST TO 6. COMPARING BETWEEN GUJRAT , KERALA AND ODISHA;GUJRAT IS LIKE “FALSE” HAVING HIGHER SUMMATION,BUT SMALLER CODE THAN KERALA.BETWEEN KERALA AND KARNATAKA,KARNATAKA IS REJECTED BECAUSE IT HAS HIGHER SUMMATION AND ALSO HIGHER CODE ,WHICH DOES NOT SATISFY “FALSE”.
C)ACCORDING TO THIRD CONDITION,KERALA AND ODISHA SATISFIES “FALSE” AND “TRUE” CONDITIONS AND STATEMENTS.
HENCE,ODISHA IS “TRUE”-LIKE STATEMENT AND ANSWER.
MORE QUESTION:
QUESTION: WHICH IS A LIQUID?
A)ICE B)WATER ?
ANSWER:CODES:ICE(17) AND CODE IS 11. WATER (67) AND CODE IS 9.
A)ACCORDING TO FIRST CONDITION, ICE IS LAST PRIORITY.
B)WATER HAS CODE NEAREST TO 6.
C)ICE IS LIKE “FALSE” AND WATER IS LIKE “TRUE” STATEMENT.HENCE,WATER IS ANSWER.
ANOTHER QUESTION: WHICH IS CALLED AS “PARADISE ON EARTH”?
A)JAMMU AND KASHMIR B)ODISHA C)NAGALAND D)BIHAR
ANSWER:CODES:
JAMMU AND KASHMIR(156) ,CODE IS 18.
ODISHA(56),CODE IS 8.
NAGALAND(54),CODE IS 17.
BIHAR(38),CODE IS 7.
A)ACCORDING TO FIRST CONDITION,J&K IS LAST PRIORITY.
B)ACCORDING TO SECOND,BIHAR IS NEAREST TO 6.IT IS TO BE COMPARED WITH ODISHA AND NAGALAND.BOTH NAGALAND AND ODISHA ARE REJECTED AS THEY DO NOT SATISFY “TRUE” STATEMENT AS COMPARED TO “FALSE” STATEMENT AS BIHAR TAKEN.
C)ACCORDING TO THIRD CONDITION,WE NOTICE HERE THAT , ODISHA DOES NOT FOLLOW “FALSE”STATEMENT AS IT HAS LESS SUMMATION AND ALSO LOWER CODE(IT SHOULD HAVE BEEN A BIGGER CODE). HENCE,J&K IS ANSWER.
IMPORTANT NOTE: THE RULE OF “SUBTRACTING FROM QUESTION MAY NOT BE NEEDED.” AND THERE IS NO “FIFTH RULE “PROBLEMS.ONLY WE HAVE THREE CONDITIONS.
***********–BAIDYANATH DASH
GENERAL RULES:
RULES FOR THIS METHOD:
1)THE HIGHEST CODE NUMBER OF GIVEN OPTIONS IS GIVEN LAST PRIORITY.
2)WE THEN SELECT THE CODE NEAREST TO TIME CODE(IE. 6).
3)WE CHECK THE OPTIONS FOR TRUE(5) OR FALSE(12).WE NOTICE HERE , ADDITION IN “TRUE “IS LESS THAN “FALSE” AND CODE IS ALSO LESS(5<12).HENCE,SIMILARLY OPTIONS ARE SELECTED.
4)IN CASE WE DO NOT FIND A SOLUTION,WE SUBTRACT THE CODE OF QUESTION ASKED TO
OPTIONS GIVEN.
********–BAIDYANATH DASH
MORE EXAMPLES:
1)QUESTION: WHICH IS SOLID?
A)ICE B)WATER?
ANSWER:CODES:ICE(11) AND WATER (9).
A)ACCORDING TO FIRST CONDITION,WE HAVE ICE LAST PRIORITY.
B)WATER IS NEAREST TO 6.
C)THEY DO NOT SATISFY THIRD CONDITION. HENCE,ICE IS NOT SIMILAR TO TRUE AND WATER IS NOT SIMILAR TO FALSE.HENCE,WATER IS REJECTED. HENCE ,ICE IS ANSwer.
ALTERNATE ANSWER:
C)ACCORDING TO THIRD CONDITION,WATER(67 AND CODE 9) AND ICE(17 AND CODE 11) IS COMPARABLE TO “TRUE “AND “FALSE” AS 67 IS NEAR 64(SUMMATION NEAR TRUE AND NOT FALSE).ALSO AS ICE (17)IS LIKE “FALSE”,ITS CODE SHOULD HAVE BEEN MORE THAN 12,BUT IT IS 11.SO IT IS “NOT FALSE”.ALSO,THE CODE OF “SOLID” IS 10. THERE IS A SEQUENCE ,11,10 AND 9.HENCE, ICE IS ANSWER.
********– BAIDYANATH DASH
QUESTION:WHICH IS SOLID? A)ICE B)WATER?
ANSWER:A)ACCORDIIG TO FIRST CONDITION,ICE(CODE 11) IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,WETER(CODE 9) IS NEAREST TO 6.
C)ACCORDING TO THIRD CONDITION,ICE(SUM 17 IS LIKE “FALSE” ,BUT ITS CODE SHOULD HAVE BEEN MORE THAN 12 IE, LIKE “FALSE” STATEMENT). HENCE,IT IS “NOT LIKE FALSE”. HENCE,IT IS “NOT FALSE”. AND , AS CODE OF “SOLID” IS 10, WE HAVE A SEQUENCE,11,10 and 9.So,ice is answer.
********–BAIDYANATH DASH
MORE QUESTIONS:
WHICH IS A GAS?
A)IRON B)COBALT C) NITROGEN D) NICKEL?
ANSWER:CODES:IRON(56 CODE IS 6),COBALT(53 CODE IS 14),NITROGEN(102 CODE IS 11),NICKEL(54 CODE IS 15).
A)ACCORDING TO FIRST CONDITION,NICKEL IS LAST PRIORITY.
B)IRON IS NEAREST TO 6.WE COMPARE IRON WITH COBALT.COBALT IS REJECTED AS IT IS NOT LIKE “FALSE”.WE AGAIN COMPARE IRON WITH NITROGEN.IRON IS REJECTED AND NITROGEN(NOW LIKE TRUE) REMAINS BECAUSE IRON IS NOT LIKE FALSE.
C)ACCORDING TO THIRD CONDITION,WE HAVE NITROGEN(LIKE TRUE) AND NICKEL IS LIKE FALSE(BUT NOT LIKE FALSE STATEMENT).HENCE, NITROGEN IS ANSWER.
EXPLANATION:
IN ABOVE ANSWER, NICKEL IS LIKE “FALSE”.BUT, AS ITS CODE IS MORE THAN 12, BUT SUM IS ALSO MORE THAN “FALSE IE, 43, IT IS NOT A “FALSE”.SO,IT IS TO BE REJECTED. HENCE, NITROGEN REMAINS WHICH IS ANSWER.
ANOTHER EXAMPLE:QUESTION: WHAT IS VALVE OF HORSE-POWER?
A)112 B)452 C)746 C)654 ?
ANSWER: CODES: 112(7),452(5),746(11),654(9).
A)ACCORDING TO FIRST CONDITRION,654 IS LAST PRIORITY.
B)BOTH 452 AND 112 IS NEAREST TO 6. BUT AS 452 HAS CODE 5 AS “TRUE”, WE REJECT 112.HENCE,452 IS NEAREST TO 6.(WE CAN COMPARE THEM WITH “TRUE” AND “FALSE”). LUCKILY. IT HAS CODE 5.NOW, WE COMPARE IT WITH 654(11).WE NOTICE, LIKE “654″ IS LIKE “TRUE” AND 452 IS LIKE FALSE”(BUT NOT “FALSE”) BECAUSE ITS CODE IS 5(”TRUE”).
C)ACCORDING TO THIRD CONDITION,WE COMPARE 654(9) AND 746(11).HERE WE HAVE, 746 AS “TRUE” AND”654 AS “FALSE”. WE HAVE CODE OF “HORSE-POWER” IS 10. WE GET A SEQUENCE OF 11,10 AND 9.ALSO,AS WE HAVE, 746 HAS CODE 11(LIKE”TRUE”) , BUT CODE OF 654 SHOULD HAVE BEEN MORE THAN 12.HENCE, 746 IS SUITABLE ANSWER.
*******–BAIDYANATH DASH
ANOTHER EXAMPLE:
QUESTION: WHICH VITAMIN IS PRESENT IN ASCORBIC-ACID?
A) A B)B-12 C)C D)K ?
ANSWER: CODES:A(2),B-12(8),C(4),K(3).
A)ACCORDING TO FIRST CONDITION,B-12 IS LAST PRIORITY .
B)ACCORDING TO SECOND CONDITION,B-12(8) AND C(4) ARE NEAR TO 6.
AS WE HAVE CODE IS MORE THAN SUM, “TRUE” IS B-12 AND “FALSE IS C(4).WE COMPARE
A(2),C(4) AND K(3).WE NOTICE THAT CODES OF K AND C ARE 3 AND 4 ,WHICH ARE LESS THAN 5 BOTH. BUT,IF C HAS SUM 3,(LESS THAN 5),K SHOULD ALSO SUM LESS THAN 5(BUT IT IS 11). HENCE IT IS REJECTED.COMPARING WITH C AND B-12,CODE OF C AND B ARE LESS AND MORE THAN 5 RESP.BUT, SUM OF B-12 IS 5(AND C IS 3).HENCE,B-12 IS REJECTED.
C)ACCORDING TO THIRD CONDITION,WE HAVE BOTH A AND C SHOWING SIMILAR(IE, EITHER TRUE OR FALSE ) AS THEIR CODES AND SUM ARE LESS THAN 5.ONE HAS TO BE THE ANSWER.
IF WE TAKE A(2) AS “FALSE” AND C(4) AS “TRUE”(NEARER TO 6 CONDITION),WE NOTICE THAT A(2)SHOULD HAVE EITHER CODE OR SUM MORE THAN 5.HENCE IT IS CONFIRMED THAT IT IS A “FALSE” STATEMENT.THAT IS WHY, C(4) IS THE ANSWER FOR THE QUESTION.
*************–BAIDYANATH DASH
MORE QUESTION:
QUESTION: WHAT IS A COOPER PAIR?
OPTIONS:ELECTRONS WITH
A)SAME SPIN B) SAME AND OPPOSITE SPIN C) DIFFERENT SPIN D) NO SPIN?
ANSWER: B) SAME AND OPPOSITE SPIN.
THIS IS A TASK TO CHECK AND CONFIRM NY CODE DETECTION METHOD.
MORE QUESTION:
QUESTION: WHICH ACID IS USE TO REPEL SNAKES ?
A) OXALIC ACID B) SULPHURIC ACID C) CARBOLIC ACID D) NITRIC ACID?
ANSWER: CODES: OXALIC ACID(19),SULPHURIC ACID(23),CARBOLIC ACID(21),
NITRIC ACID(19).
A)ACCORDING TO FIRST CONDITION,CARBOLIC ACID IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,BOTH OXALIC AND NITRIC ACIDS ARE NEAREST TO 6.ONE HAS TO REMAIN.NITRIC ACID IS TRUE,BUT OXALIC ACID IS “NOT” FALSE STATEMENT.HENCE NITRIC ACID IS NEAREST TO 6.SULPHURIC ACID IS REJECTED BECAUSE IT IS NOT LIKE “TRUE” STATEMENT.
C)ACCORDING TO THIRD CONDITION, WE NOTICE HERE THAT AS SUM OF CARBOLIC ACID IS LESS THAN NITRIC ACID,IT IS TAKEN AS “FALSE”,BUT ALSO AS DIFFERENCE BETWEEN CODES AND SUMS IN BOTH ARE COMPARABLE UNLIKE “TRUE” AND ” FALSE” ITIS AN AMBIGUOUS .BUT, AS QUESTION IS CORRECT, NITRIC ACID IS REJECTED AS 19 IS MUCH BIGGER THAN 5(COMPARING TO 21 WHICH IS NEAR TO 12). HENCE, CARBOLIC ACID IS ANSWER.
MORE QUESTION:
QUESTION: WHO IS THE SUPREME COMMANDER OF FORCES?
A)PRESIDENT B)PRIME MINISTER C)VICE- PRESIDENT D)ATTORNEY GENERAL?
ANSWER: CODES: PRESIDENT(11),PRIME MINISTER(19),VICE-PRESIDENT(18),ATTORNEY GENERAL(24).
A)ACCORDING TO FIRST CONDITION, ATTORNEY GENERAL IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,PRESIDENT IS NEAREST TO 6.WE HAVE, CODE AND SUM IN PRIME MINISTER IS MORE. HENCE, HE IS NOT.SIMILARLY, SAME IS WITH VICE-PRESIDENT.
C)ACCORDING TO THIRD CONDITION,ATTORNEY GENERAL HAS BOTH CODE AND SUM MORE. HENCE, PRESIDENT IS THE CORRECT OPTION.
*********–BAIDYANATH DASH
MORE QUESTIONS:
QUESTION:IF HEADIS H, TAIL IS T THEN, WHAT IS PROBALITY IN HH,HT,TH,TT ?
(A)HH(16 CODE IS 9)
(B)HT(28 CODE IS 3)
(C)TH(28 CODE IS 3)
(D)TT(40 CODE IS 6).
ANSWER: ACCORDING TO FIRST CONDITION,PRIORITY OF HH IS LAST.
B)ACCORDING TO SECOND CONDITION, TT IS NEAREST TO 6.IT IS TAKEN AS ” TRUE”.BOTH HT AND TH ARE REJECTED HERE AS THEY DO NOT FOLLOW “FALSE”.
C)ACCORDING TO THIRD CONDITION,SUM 16 IN HH IS TOO SMALL COMPARING TO”FALSE” ,AND ALSO TT AS “TRUE” DOES NOT SATISFY THE CONDITION.
NOTE: IF WE TAKE HH,HT,TH AND TT IN QUADRANT FORM,TT(”TRUE” COMES IN 1ST QUADRANT,HH IN 4TH QUADRANT AS “FALSE”, TH IN 2ND AND HT IN 3RD QUADRANT).
NOTE: IF A QUADRANT IS 90 DEGREES(100% IN ANY QUADRANT).
INTERESTING FINDINGS:
A)CODES 9 AND 6 WILL OVERLAP TO FORM 8 IN DIGTIAL FORMAT(AS IN LCDS).
B)CODES 3 AND 3 WILL FORM DIGITAL 8 AS MIRROR IMAGES.
********–BAIDYANATH DASH
MORE QUESTIONS:
QUESTION: WHAT IS PROBABILITY OF FINDING SOWMYA (A GIRL) IN JAYANAGAR(BENGLURU)?
A)50% B)60% C)40% D) 57.33% ?
ANSWER: AS LETTER Z (26 CORROSPONDS TO 100%), IF WE DIVIDE DIFFERENCE OF S(19)AND J(10),IE,WE GET 19-10=9(I).AGAIN IF WE DIVIDE IT BY 4, WE GET RESULT IN 1ST QUADRANT ONLY. THEREFORE,9/4=2.25. AGAIN,2.25*26=57.33. ALSO, (2.25*90/100)=22.25 DEGREES(LETTER V).HENCE, WE FIND THAT SHE RESIDES IN FIRST QUADRANT.NOW, JAYANAGAR HAS 9 BLOCKS AND 22.25 CORROSPONDS TO 3RD BLOCK IN JAYANAGAR.
************–(BAIDYANATH DASH)
MORE QUESTIONS:
QUESTION:WHICH IS THE POWERHOUSE OF CELL?
A)MITOCHONDRIA B)CYTOPLASM C)RIBOSOME D) NUCLEUS?
ANSWER: CODES:MITOCHONDRIA(129 CODE IS 15)
CYTOPLASM(124 CODE IS 16)
RIBOSOME(96 CODE IS 14)
NUCLEUS(95 CODE IS 12)
ANSWER: ACCORDING TO FIRST CONDITION,CYTOPLASM IS LAST PRIORITY.
B)NUCLEUS IS NEAREST TO 6.AS CYTOPLASM AND RIBOSOME DO NOT FOLLOW “TRUE” STATEMENT,COMPARING WITH MITOCHONDRIA,THEY ARE REJECTED.
C)ACCORDING TO THIRD CONDITION, NUCLEUS IS DOES NOT FOLLOW “FALSE” STATEMENT AS
CODE IS LESS THAN THAT OF MITOCHONDRIA.
HENCE, (A)MITOCHONDRIA IS CORRECT ANSWER.
MORE QUESTION:
QUESTION: WHICH RADIATION HAS HIGHEST PENETRATING POWER?
A) ALPHA B)BETA C)GAMMA ?
ANSWER: CODE:
ALPHA(38 CODE IS 7)
BETA(28 CODE IS 5)
GAMMA(35 CODE IS 13)
A)ACCORDING TO FIRST CONDITION, GAMMA IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION, BETA AND ALPHA BOTH ARE NEAREST TO 6.ALPHA IS “TRUE” LIKE AND ” BETA” IS NOT “FALSE” LIKE AS ITS CODE AND SUM BOTH ARE LESS.BETWEEN ALPHA AND GAMMA,ALPHA IS “FALSE”AND GAMMA IS ‘TRUE”.
HENCE, GAMMA IS THE RIGHT OPTION.
DEAR MADAM, KINDLY TELL HOW MANY OF MY FINDINGS ARE SELECTED. THREE OF THE WERE
NEW.
–BAIDYANATH DASH
SOME OF MY WRITINGS ARE DELETED FROM THIS SITE.IS IT SELECTED?
–BAIDYANATH DASH
MORE QUESTIONS:
QUESTION:IN WHICH STATE THE MOLECULES ARE FARTHEST FROM EACH OTHER?
A)SOLID B)LIQUID C)GAS?
ANSWER: CODES:SOLID(59 CODE IS 10),LIQUID(72 CODE IS 15),GAS(27 CODE IS 12).
A)ACCORDING TO FIRST CONDITION,LIQUID IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION, GAS IS NEAREST TO 6.LIQUIDHAS BOTH CODE AND SUM MORE COMPARING WITH GAS;HENCE IT IS REJECTED.
C)ACCORDING TO THIRD PRIORITY, WE NOTICE THAT RATIO OF (64-59):10 AND (43-27):12
AND THAT 64:5 AND 43:12 DOES NOT MATCH . BUT THAT OF GAS ONLY REMAINS AS AN ANSWER.
BULLET-PROOF JACKET:
1)THE JACKET IS FOR PROTECTION OF BODY FROM BULLETS.
2)WE USE HERE ALUMINIUM,TUNGSTEN AND NANOMATERIALS.
3)ALUMINIUM IS LIGHT IN WEIGHT.TUNGSTEN IS STRONG AND HEAT RESISTANT.
4)NANOWIRES CAN BE USED IN FORM OF NETS OR “NANONETS” TO COVER THE MOSAIC FORM OF JACKET.
5)THE WAIST WRAP IS ALSO PREPARED.ALSO, A COMPLETE DRESS COVERED BU NANONETS CAN BE BUILD.THIS WILL BE FOR TOTAL-BODY PROTECTION.
6)NANOWIRES ARE STRONG AND EASY TO MOULD INTO ANY DRESS.
7)WE CAN HAVE BUTTONS IN BETWEEN FOR EXTRA SHIELD.
8)PRINCIPLE:THE JACKET WILL PROTECT AS IT IS STRONG AND ALUMINIUM BEING LIGHT CAN BE CARRIED EASILY.
***************–BAIDYANATH DASH
SOME MORE QUESTIONS:
QUESTION: WHICH NEWSPAPER HAS HIGHEST CIRCULATION IN INDIA?
A) THE HINDU B) THE TIMES OF INDIA C) THE HINDUSTAN TIMES D)THE TELEGRAPH ?
ANSWER:CODES:
A)THE HINDU( 89 CODE IS 16)
B)THE TIMES OF INDIA(159 CODE IS 19)
C)THE HINDUSTAN TIMES(209 CODE IS 19)
D)THE TELEGRAPH (125 CODE IS 20)
A)ACCORDING TO FIRST CONDITION,THE TELEGRAPH HAS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,THE HINDU IS NEAREST TO 6.BETWEEN THE HINDU AND THE HINDUSTAN TIMES, AND THE TIMES OF INDIA, “FALSE” IS THE HINDU.BETWEEN REST TWO, WE NOTICE THAT THE TIMES OF INDIA IS ” TRUE” AND THE HINDUSTAN TIMES IS NOT DUE TO RATIO OF THEIR CODE AND SUM.
C)ACCORDING TO THIRD CONDITION,THE TIMES OF INDIA IS “TRUE” AND THE HINDU IS
“FALSE” AS PER TRUE AND FALSE STATEMENTS.WE SELECT THE TRUE ONE.
SOME MORE QUESTIONS:
,WATER(67 CODE IS 9), AIR(28 CODE IS 4).
QUESTION: WHERE LIFE ORIGINATED ON EARTH?
A) LAND B) WATER C) AIR?
ANSWER:LAND(31 CODE IS
A) ACCORDING TO FIRST CONDITION, WATER IS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,LAND AND AIR ARE NEAREST TO 6.COMPARING LAND
AIR, LAND (SUM 31 ) IS NEAR “FALSE SUM”, BUT AIR IS NOT “TRUE” AS CODE IS 4, BUT SUM IS 28.HENCE WE SELECT LAND.
C)ACCORDING TO THIRD CONDITION,COMPARING CODES AND SUM OF TRUE AND FALSE, 8*4=32 (NEAR 31 AND NOT 67)AND 8*8=64(NEAR 67);AS WE FOR “TRUE” STATEMENT COMPARISION TO GET THE ANSWER. WE HAVE TAKEN 67 AS SUM NEAR TO “TRUE” FOR REFERENCE.
**********–BAIDYANATH DASH
MORE QUESTIONS:
1)WHICH HAS ‘EYES’?
A)POTATO B)TOMATO C)ONION C)MELON ?
ANSWER: POTATO
KINDLY CONFIRM THIS METHOD.
MRI USING A SINGLE MAGNET:
1)WE WANT TO DEVELOP A MRI USING A SINGLE MAGNET. THE CONCEPT WILL UTILIZE THE EARTH’S NATURAL MAGNETIC FIELD AS A SUBSTITUTE FOR THE ANOTHER MAGNET USED IN MRIs.
2)EARTH IS A MAGNET WITH LOW MAGNETIC FIELD STRENGTH, WHICH IS SUITABLE TO CONSTRUCT THE MODERN MRIs.
3)CONSTRUCTION:
A) A RECTANGULAR MAGNET WITH A CIRCULAR RIM,AS THAT OF CT-SCANS, WILL BE SUSPENDED FROM THE CEILING.
B)THIS MAY BE A CIRCULAR MAGNET,WITH MULTIPLE MAGNETIC SLOTS TO ADJUST THE FIELD(AS IN FLOOD LIGHTS).
C) THE HELMHOLZ –COIL WHICH SURROUNDS THE SUBJECT(PATIENT),WILL BE PLACED ON A HYDRAULIC STAND OR SIMPLE STANDS IN BETWEEN THE MAGNET AND THE EARTH.
D)A SMALL MAGNETIC COMPASS IS NEEDED TO ADJUST THE EARTH’S MAGNETIC( NORTH-SOUTH) DIRECTION WITH THE SUSPENDED MAGNET ON THE CEILING.
E)THE ADJUSTMENT IS DONE BY THE COMPUTER .IE. IT WILL EITHER ROTATE THE MAGNET SUSPENDED ALONG THE RIM OR WILL USE THE MAGNETIC SLOTS FOR THE FIELD.
F)WE CAN ADJUST THE HELMHOLZ COIL BEFOREHAND ALONG THE EARTH’S MAGNETC FIELD.HENCE, WE GET THE PROPER ALIGNMENT OF THREE,IE. MAGNET,COIL AND EARTH’S MAGNETIC DIRECTION.
G)BODY HAS WATER AND HAS PROTON IN HYDROGEN,WHICH SHOULD ATTAIN THE LARMOUR FREQUENCY.
H) A SPECTROMETER TO DETECT THE CHANGES IN WAVELENGTHS OF AFFECTED PROTONS BY MAGNETIC FIELD IN DEFECTIVE AND NORMAL REGIONS OF BODY IS PRESENT.
I) THE DIGITAL IMAGE PROCESSING SOFTWARE WILL PROCESS THE IMAGE IN 2- DIM. OF A 3-DIM. OBJECT AND THE SLICES ARE FURTHER PROCESSED TO GET 3-DIM. VIEW .
J)THE MAGNETIC STRENGTH OF A SINGLE MAGNET IS OF- COURSE WILL BE HIGHER THAN A ONE OF THE SINGLE MAGNETS OF MRI.WE WILL GET THE STRENGTH BY EXPERIMENT.
K)THE MAGNETIC SLOTS MAY USE THE COIL WINDINGS TO PASS ELECTRIC CURRENT NEEDED FOR A PERMANENT MAGNET.
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–BAIDYANATH DASH
Reply
BAIDYANATH DASH says:
September 15, 2009 at 10:46 pm
TALKING FASCILITY IN WRIST WATCHES
1)WRIST WATCHES CAN BE USED FOR COMMUNICATION PURPOSES, TO TALK.
2)AS MOST PEOPLE WEAR WATCHES,IT IS AN ADVANTAGE TO USE IT IN EMERGENCIES,EG. IN CALAMITIES ,HEALTH PROBLEMS,ETC.
3)THE WATCH WILL USE GSM TECHNOLOGY AS IN MOBILE PHONES OR PAGERS.A MINI RECEIVER,TRANSMITTER,A MODEM FOR SIGNALS ARE NEEED.
4)A BUZZER MAY BE SOUNDED ON RECEIVER’S END WHICH WILL INDICATE AN EMERGENCY.
5)THE POWER IS PROVIDED BY BATTERY OF THE WATCH OR PULSE OF WRIST.
6)THE DIALING NUMBER IS INSERTED BY TALKING OR SPEAKING OUT THE NUMBER AT TRANSMITTER END, ONCE BUTTON IS SWITCHED ON.
7)THE COMMUNICATION IS FACILITATED VIA TELEPHONE OR MOBILE LINES OR BANDWIDTH.FOR TELEPHONIC COMMUNICATION A SERIAL PORT OR USART IS NEEDED AND FOR MOBILE LINE,GSM TECHNOLOGY IS SUITABLE WITH RS-232 .
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–BAIDYANATH DASH
MORE QUESTIONS:
QUESTION:WHO IS PRESIDENT OF U.S.A?
A)BILL CLINTON B) BILL GATES C) BARACK OBAMA D) GEORGE WASHINGTON ?
ANSWER:CODES(BILL CLINTON CODE IS 16),BILL GATES(CODE IS 12), BARACK OBAMA(CODE IS 16),GEORGE WASHINGTON(CODE IS 20).
A)ACCORDING TO FIRST CONDITION, GEORGE WASHINGTON HAS LAST PRIORITY.
B)ACCORDING TO SECOND CONDITION,BILL GATES IS NEAREST TO 6.COMPARING WITH BILL CLINTON AND BILL GATES, RATIO OF SUM IS MORE IN BILL CLINTON(122) .SO IT IS NOT “TRUE”.COMPARING WITH BILL GATES,”FALSE” AND BARACK OBAMA,” TRUE” , LATER IS SELECTED.
C)ACCORDING TO THIRD CONDITION,BARACK OBAMA IS “FALSE” AND GEORGE WASHINGTON IS NOT “TRUE” AS CODE AND SUM BOTH ARE MORE.
***************–BAIDYANATH DASH
SOME OF MY WRITINGS ARE DELETED:
A)OPTICAL RADAR.
B)BIOGAS THERMAL-POWER PLANT USING BIOMASS AND SEA WATER.
C)OPTO-VISION CAMERA .
D)ELECTRIC CYCLE .
IMMORTAL STEM CELLS:
I WANT TO NAME THE IMMORTAL STEM CELLS I HAVE WRITTEN AS ” SANJEEVANI PACKETS”
AS ENERGY PACKETS (PHOTONS).
NUCLEAR SPRAYS:
1)WE HAVE Y CHROSOME(DNA OR GENE) HAS NEUTRON .
2)WE INJECT THIS DNA INTO ONCOLOGICAL VIRUSES.
3)A BACTERIA HAVING RECOMBINANT DNA WILL GROW IN NUTRIENT MEDIUM OR SUBSTRATE.
4)THE VIRUS WILL MULTIPLY AND PROLIFERATE ON BACTERIA INJECTED WITH RADIOCTIVE SUBSTANCES.
5)THE COLLISION BETWEEN HIGH SPEED NEUTRONS AND RADIOCTIVE BACTERIA WILL RESULT NUCLEAR FISSION REACTION.
6)THE VIRUS ARE LIVING AND NON-LIVING.WE GIVE ENERGY TO NON-LIVING PART.THE KINETIC ENERGY OF VIRUS WILL INCREASE(BROWNIAN MOTION).HENCE HIGH SPEED COLLISIONS.
7)MULTIPLE NUCLEAR REACTIONS CAN ALSO OCCUR(AS IN ANN(ARTIFICIAL NEURAL NETWORKS).
9)WE BUILD COCONUT-SHAPED NUCLEAR REACTOR WHERE REACTION TAKES PLACE AT CORE.
10)WE CAN MAKE “NUCLEAR SPRAYS” AND “MINI REACTRORS” BY THIS METHOD.
*******************–BAIDYANATH DASH
NOTE:
1)COCONUT SHAPED REACTOR MEANS “CHAMBERS INSIDE CHAMBERS” LILE COCO’NUT’.
2)RADIOACTIVE SUBSTANCE IS URANIUM-235(92).
3)WE CAN HAVE ILLUMINATION TECHNOLOGY “LIKE BULBS FOR SPRAYS.
METAL AND BODY DETECTOR :
1)WE HAVE A ROD MADE OF ALUMINIUM.WE MAKE IT A SHAPE OF A HORSE-SHOE (RECTANGULAR)MAGNET.IT IS A JACKET TO BE WORN.
2)THE CT-SCAN(X-RAY) CAMERAS ARE ON ONE SIDE OF ROD .THEY EMIT X-RAYS.
3)THE DETECTORS ARE ON OTHER SIDE OF ROD TO DETECT THE PRENCE OF ANY METAL.
4)THE BASE OF HORSE-SHOE RECTANGULAR HAS SUPERCONDUCTING PERMANENT MAGNETS.BY USING COOPER-PAIR IMAGING TECHNOLOGY(AS MRI PRINCIPLE),WE DETECT PRESENCE OF ANY BIOLOGICAL OR CHEMICAL SUBSTANCES IN BODY(IT MAY BE NARCOTICS).
5)THE CIRCUIT IS MAINLY OF OPTOELECTRONIC CIRCUIT. WE EXTENSIVELY USE PHOTONICS FOR COST EFFECTIVENESS.
6)A WI-FI HAND HELD DEVICE OR A COMPUTER IS PRESENT TO DISPLAY THE OUTPUT.THE OUTPUT FOR METAL-DETECTION AND BODY DETECTION WILL BE DONE BY SOFTWARES.
7)WE CAN ALSO BUILD ENTRANCE GATES BY USING THIS TECHNOLOGY IN IMPORTANT PLACES.
***********–BAIDYANATH DASH
A VIEW ON DIMWNSIONS IN SPACE:
A)WE KEEP THREE ELECTRONS ALONG THREE DIRECTION :X, Y AND Z COORDINATES.
2)WE KNOW THAT A MASS ALWAYS HAS LENGTH,BREADTH AND HEIGHT AND IT OCCUPIES SPACE.MEANS,IT HAS THREE DIMENSIONS.
3)WE SEE THAT FOR THREE ELECTRONS,WE HAVE 3+3+3=9 DIMENSIONS.
4)ONE MORE DIMENSION IS THAT OF TIME.
5)HENCE WE GET 10 DIMENSIONS .
6)WE CAN ASSUME ALSO A CIRCLE WITH SIX BEADS ON ITS CIRCUMFERENCE.LET US TAKE THEM AS A WHITE AND A BLACK HOLE ALTERNATIVELY.THAT IS ONE IS SOURCE AND OTHER IS SINK.
7)AT THE CENTER OF CIRCLE,WE KEEP AN ANOTHER BEAD.SO, A SPHERE SURROUNDED BY 6 OTHER SPHERES.WE HAVE (3*MC^2) FOR THREE WHITE HOLES.IF ONE MASS HAS 3 DIMENSIONS, WE HAVE, 3*3=9 DIMENSIONS. ALSO THIS IS WITH RESPECT TO TIME(ONE MORE DIMENSION).THEREFORE, WE HAVE 10 DIMENSIONS(MORE THAN 4 AS WE TILL THINK).
*********–BAIDYANATH DASH
HOW TO GET 3 DIMENSIONS FROM A POINT MASS:
1)LET US TAKE A POINT MASS.STRETCH THAT(BY ANY MEANS) ALONG ONE DIRECTION.WE GET 1 DIMENSION .
2)AGAIN MAKE A CIRCLE FROM THAT LENGTH. WE GET 2 DIMENSIONS.
3)NOW,TRY TO BRING IT TO ORIGINAL SHAPE, WE GET LENGTH ,BREADTH AND HEIGHT.HERE IS THREE DIMENSION.
AN INSIGHT ON ENERGY FORMULAE:
1)WE HAVE,ACCORDING TO EINSTEIN’S EQUATION,
E=M*C^2
2)ENERGY OF ELECTRON=8.19*10^-14 J.
3)LET US TAKE SQUARE OF THIS VALUE.THAT IS ,
E(ELECTRON)^2=66.0761*10^-14*10^-14=66.0771*10^-28.
4)WE OBSERVE HERE THAT THE MAGNITUDE BECOMES LESS ON SQUARING.
5)ALSO,IF WE TAKE MASSES 0.2 AND 0.2 KG,WE HAVE M*M=0.2*0.2=0.4.
0.4 IS LESS THAN O.2 AND 0.2.HENCE, ENERGY VALUE WILL BE LESS AS SPEED OF LIGH(C) IS A CONSTANT VALUE.
6)THIS IS ONLY TRUE FOR MASS EQUAL TO OR MORE THAN 1 KG MASS.SO,FOR ELECTRON(MASS LESS THAN I KG),THIS EQUATION DOES NOT HOLD GOOD MATHEMATICALLY.
7)ENERGY IS A SCALAR AND ON MULTIPLYING, ITS VALUE SHOULD BE MORE .BUT,FOR MASS LESS THAN 1 KG, THERE IS A DEVIATION.
*********–BAIDYANATH DASH